Match the GCF with the factors.
1 answer:
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Answer:
-
Step-by-step explanation:
Step 1: Add the numerator fractions.
2/5 + 3/10
Here we have to find LCD, the LCD of 5 and 10 is 10
(2*2) + 3 4 + 3
Therefore, 2/5 + 3/10 = --------------- = ------------------
10 10
= 7/10
Step 2: Now substitute 2/5 + 3/10 = 7/10 in the given fraction, we get
7/10
= ----------
-7/9
If we have fraction over fraction, we have to find the reciprocal of denominator fraction and multiply.
The reciprocal of -7/9 is -9/7
Step 3: Now multiply 13/10 and -9/7
= (7/10) x (-9/7)
= -9/10
=-9/10
The answer is -
Answer:
The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.
Minimum cost=2046.16 cents
Step-by-step explanation:
Given that a rectangular box with a volume of 684 ft³.
The base and the top of the rectangular box is square in shape
Let the length and width of the rectangular box be x.
[since the base is square in shape, length=width]
and the height of the rectangular box be h.
The volume of rectangular box is = Length ×width × height
=(x²h) ft³
(1)
The area of the base and top of rectangular box is = x² ft²
The surface area of the sides= 2(length+width) height
=2(x+x)h
=4xh ft²
The total cost to construct the rectangular box is
=[(x²×20)+(x²×15)+(4xh×1.5)] cents
=(20x²+15x²+6xh) cents
=(25x²+6xh) cents
Total cost= C(x).
C(x) is in cents.
∴C(x)=25x²+6xh
Putting
Differentiating with respect to x
To find minimum cost, we set C'(x)=0
ft.
Putting the value x in equation (1) we get
≈36.23 ft.
The dimensions of the rectangular box is 36.23 ft×36.23 ft×4.345 ft.
Minimum cost C(x)=[25(4.345)²+10(4.345)(36.23)] cents
=2046.16 cents