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Masja [62]
2 years ago
9

What is the function equation for the input/output table?

Mathematics
1 answer:
Nookie1986 [14]2 years ago
4 0

Answer:

y = x - 8

Step-by-step explanation:

I plugged iin for the values and checks out.

Hope this helps!

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There are n machines in a factory, each of them has defective rate of 0.01. Some maintainers are hired to help machines working.
frosja888 [35]

Answer:

a) 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b) 1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c) ∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

Step-by-step explanation:  

Given that;

if n ⇒ ∞

p ⇒ 0

⇒ np = Constant = λ,  we can apply poisson approximation

⇒ Here 'p' is small ( p=0.01)

⇒ if (n=large) we can approximate it as prior distribution

⇒ let the number of defective items be d

so p(d) = ((e^-λ) × λ) / d!

NOW

a)

Let there be x number of repairs, So they will repair 20x machines on time. So if the number of defective machine is greater than 20x they can not repair it on time.

λ[n0.01]

p[ d > 20x ] = 1 - [ d ≤ 20x ]

= 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b)

Similarly in this case if number of machines d > 80x/3;

Then it can not be repaired in time

p[ d > 80x/3 ]

1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c)

n = 300, lets do it for first case i.e;

p [ d > 20x } ≤ 0.01

1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.01

⇒ ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.99

⇒ ∑²⁰ˣ_k=0 (λ^k)/k! = 0.99e^λ

∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

8 0
2 years ago
The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected
mr Goodwill [35]
We have that if we assume standard exponential growth, the equation of the population will be:7000*e^{kt} if we start counting from the moment that the population was 7000. We are given that 7000* e^{5k}=12000, namely that P(5)=12000 and we need to find 7000e^{(5+5)k}=7000e^{10k}. Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000\frac{12000^2}{7000^2}= 20571 people.
3 0
3 years ago
I need help please will mark the brainliest
jok3333 [9.3K]

Answer:

i cant seee the picture

Step-by-step explanation:

can u retake it

8 0
3 years ago
A point in the figure is selected at random. Find the probability that the point will be in the part that is NOT shaded.
creativ13 [48]

Answer:

About 20%

Step-by-step explanation:

The probability of a point on the un-shaded region will be given by;

Area of the shaded region/total area

Considering that the circles are of the same size, then the length of the square is 2d

Area of the square = 4d²

Area of the shaded = (4d² -4π(d/2)²

                                = 4d² -πd², but π = 22/7

                                = 6/7d²

Probability = (6/7d² ÷ 4d²) × 100%

                  = (6/28 d²) × 100%

                  = 21.42 %

Therefore; the answer is about 20%

3 0
2 years ago
13. A shop owner spent $540 to purchase a stock of
Daniel [21]

Answer:

Step--by--step explanation:

3 0
3 years ago
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