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3 years ago

8

Which number makes this sentence true? 7.8×3.6×1=7.8×? 1,3.6,4.6,7.8

1 answer:

marin [14]3 years ago

5 0

In the left hand side, you're multiplying 7.8 by $3.6\times 1$

In the right hand side, you're multiplying again 7.8 by a mysterious number.

So, the unknown number must be $3.6\times 1$

Every number remains unchanged when multiplied by 1, so the answer is 3.6

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Explain why the vertical line test is used to determine if a graph represents a function

labwork [276]

Answer:

A function can only have one y value for each value of x, ie., y = f(x). The vertical line test verifies this. If you move a vertical line across the grid, your graph should never intersect this line at more than one place at a time. If it intersects at 2 or more places, there is no way a y=f(x) can make this happen, so then it is not a function.

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4 years ago

What is the formula for x^2-11x+10

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Answer:

In the expression

${x}^{2} - 11x + 10$

a in the formula will be substituted for 1

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1 year ago

Factor the expression

charle [14.2K]

Hi

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4 years ago

Please confirm my answer

Verdich [7]

Yes your answer is correct

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3 years ago

Read 2 more answers

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

4 years ago