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Scorpion4ik [409]
2 years ago
10

Can someone please help me with this

Mathematics
2 answers:
k0ka [10]2 years ago
5 0

Answer: 3x^6+x^5-x^4-6x^3+x^2+3x-1

Step-by-step explanation:

 (3x^2+x-1)(x^4-2x+1)

=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1

=3x^6+x^5-x^4-6x^3+x^2+3x-1

Hope this helps!! :)

Please let me know if you have any question

qwelly [4]2 years ago
3 0

Answer:

the thing below xd

Step-by-step explanation:

(3x^{2} +x-1)(x^4-2x+1)\\\\=3x^2(x^4-2x+1)\\+x(x^4-2x+1)\\-1(x^4-2x+1)\\\\=3x^6-6x^3+3x^2\\+x^5-2x^2+x\\-x^4+2x-1\\\\=3x^6+x^5-x^4-6x^3+(3-2)x^2+(1+2)x-1\\\\=3x^6+x^5-x^4-6x^3+x^{2} +3x-1

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Which represents the polynomial written in standard form? 8x2y2 – StartFraction 3 x cubed y Over 2 EndFraction 4x4 – 7xy3 –7xy3
olga55 [171]

Polynomial equation is a equation which is formed with coefficients variables and exponents with basic mathematics operation and equality sign. The given option the option A matches correctly with the above polynomial equation which is,

-7xy^3+8x^2y^2-\dfrac{3x^3y}{2}+4x^4

Hence the option A is the correct option.

<h3>Given information-</h3>

The given polynomial equation in the problem is,

8x^2y^2-\dfrac{3x^3y}{2}+4x^4-7xy^3

<h3>Polynomial equation </h3>

Polynomial equation is a equation which is formed with coefficients variables and exponents with basic mathematics operation and equality sign.

In the above polynomial equation the variable are<em> x </em>and <em>y </em>and the highest power of the variable <em>x</em> is four and highest power of the variable <em>y</em> is three.

Arrange the polynomial equation in the power of the variable <em>x. </em>Thus,

4x^4-\dfrac{3x^3y}{2}+8x^2y^2-7xy^3

Arrange the polynomial equation in the power of the variable <em>y. </em>Thus,

-7xy^3+8x^2y^2-\dfrac{3x^3y}{2}+4x^4

From the given option the option A matches correctly with the above polynomial equation which is,

-7xy^3+8x^2y^2-\dfrac{3x^3y}{2}+4x^4

Thus the option A is the correct option.

Learn more about the polynomial equation  here;

brainly.com/question/25958000

8 0
2 years ago
Determine if the statement is always, sometimes or never true.
mojhsa [17]

Answer:

I think its c

Step-by-step explanation:

I'm pretty sure you need decimals to make it an irrational number

3 0
3 years ago
I need details please
m_a_m_a [10]
Ok, first you need to read a - g and mark down the information you know. Also, this continuous function can look pretty much like anything long as it has the a - g constraints/rule. 

A) We know the domain(x values) is between -10 to infinity
(-10,-9,-8,-7,-6,-5,-4,-3-,2,-1,0,1,2,3,4,5,6,7,8,9,10, to ---------> infinity)
B) We know the range(y values) is between -6 to infinity
(-6,-5,-4,-3-,2,-1,01,2,3,4,5,6,7,8,9,10, to ---------> infinity) 

C) Next we know f(0) = f(4) = 0
So we know when x = 0  that f(0) = 0 or we can say  y = 0. We also know when f(4) = 0 so when x = 4 y = 0. So we have two points (0,0) and (4,0) that our function will be on so plot the two points (0,0) (4,0)

D) It tells us that f(x) (y) is increasing between the x values (-10,-6)  or (-2,2) or (4, to infinity)

E) It tells us that f(x) (y) is decreasing between the x values (-6,-2) or between (2,4)

F) Tells us that f(x) (y) is greater than or equal to between the x values of [-8,-4] or between the x values [0, to infinity) so this lets us know our drawing is going to be above or equal to 0 when we are in the values [-8,-4] or [0, to infinity)

G) Tells us that f(x) (y) is less than 0 when the function / drawing is between the x values of (-10, -8) or (-4,0)  

The picture is what the function could look like. It can be different but needs to following the rules that are given 




3 0
3 years ago
The fish tank has side lengths 20in, 10in and height 15in. The water level is two inches below the top of the tank. A glass sphe
Kitty [74]

Answer:

Part 1) The new distance from the water to the top of the tank is 1.979\ in

Part 2) The maximum number of balls that can be put into the tank with the tank not overflowing is 95

Step-by-step explanation:

step 1

Find the total volume of the tank

V=20*10*15=3,000\ in^{3}

step 2

Find the volume of the tank if the water level is two inches below the top of the tank

V=20*10*(15-2)=2,600\ in^{3}

step 3

Find the volume of the glass sphere

The volume of the glass sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

r=1\ in

assume

\pi=3.14

substitute

V=\frac{4}{3}(3.14)(1)^{3}

V=4.2\ in^{3}

step 4

What is the new distance from the water to the top of the tank?

we know that

2 in -----> represent (3,000-2,600)=400\ in^{3}

so

using proportion

Find how many inches correspond a volume of 4.2\ in^{3}

\frac{2}{400}\frac{in}{in^{3}}=\frac{x}{4.2}\frac{in}{in^{3}}\\ \\x=4.2*2/400\\ \\x=0.021\ in

The new distance from the water to the top of the tank is

2-0.021=1.979\ in

step 5

Find how many of these balls can be put into the tank with the tank not overflowing

we know that

The volume of one ball is equal to  4.2\ in^{3}

using proportion

\frac{1}{4.2}=\frac{x}{400}\\ \\x=400/4.2\\ \\x=95.23\ balls

therefore

The maximum number of balls that can be put into the tank with the tank not overflowing is 95

4 0
3 years ago
I dont quite understand this.. Check the picture and help
wariber [46]

5) 74.925

6) 470

i think this is correct but i'm not completely sure

6 0
2 years ago
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