Answer: There are 4 average cars in the system.
Step-by-step explanation:
Since we have given that
Arrival rate = λ = 4 cars per hour
Service rate = μ = 5 cars per hour
We need to find the average number of cars in the system.
So, Average number of cars would be

So, it becomes,

Hence, there are 4 average cars in the system.
Given that angle ABC is congruent to angle DEF and angle GHI is congruent to angle DEF, angle ABC is congruent to angle GHI by the Transitive Property of Equality. The Transitive Property of Equality states that if a = b and b = c, then a = c.
The answer is gonna be 15
Answer:
d = 15
Step-by-step explanation:
Divide the numbers


Multiply all terms by the same value to eliminate fraction denominators

Cancel multiplied terms that are in the denominator

Multiply the numbers

Move the variable to the left

Hence, d= 15.
[RevyBreeze]
H(t)=h0+vt-(at^2)/2 we can assume that this problem is near to the earth's surface so a≈32ft/s^2
h(t)=h0+vt-16t^2 now you need to plug in the initial velocity where v is and the initial height where h0 is...