Answer:
125
Step-by-step explanation:
A full circle is 360°
80+85+70=235
360-235=125
Answer:
The answer is negative. Answer choice B
Step-by-step explanation:
Here is the question:
-3^40(5.6/2.1)
According to order of operations, we must do -3^40 first.
Its important to note that -3^40 is different than (-3)^40. In the problem you specified, the ^40 only applies to the 3, not -3. So, first we do 3^40 which is a huge number. And then, we need to add a negative symbol to that huge number. So now we have a massive negative number multiplied by 5.6/2.1, which is obviously positive. Obviously, a negative number multiplied by a positive number is still negative. Therfore, the answer is negative.
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A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.
We can use the Pythagorean formula to find the other leg of the right triangle.
a²+b²=c²
Where a and b are the legs of the triangle and c is the hypotenuse.
According to the given problem,
one leg: a= 5m and hypotenuse: c=13√5 m.
So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,
5²+b²=(13√5)²
25 + b² = 13²*(√5)²
25 + b² = 169* 5
25+ b² = 845
25 + b² - 25 = 845 - 25
b² = 820
b =√ 820
b = √(4*205)
b = √4 *√205
b = 2√205
b= 2* 14.32
b = 28.64
So, b= 28.6 (Rounded to one decimal place)
Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).
Answer:
111.2
Step-by-step explanation:
The square root and the ^2 cancel each other out so the number stays the same or 111.2
Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
