Answer:
Step-by-step explanation:
<u>differentiating numerator wrt x :-</u>
(sinx)' = cos x
<u>differentiating denominator wrt x :- </u>
(1 + cos x)' = (cosx)' = - sinx
- Let's say the denominator was "v" and the numerator was "u"
here,
- since u is the numerator u= sinx and u = cos x
- v(denominator) = 1 + cos x; v' = - sinx
since cos²x + sin²x = 1
diving numerator and denominator by 1 + cos x