(a) The vertical motion equation for the ball is h = 8 + 48t - 16t².
(b) The time for the ball to hit the ground is 3.15 s.
(c) The time for the ball to travel 56 ft above the ground is 0.79 s.
<h3>Vertical motion equation for the ball</h3>
The vertical motion equation for the ball is calculated as follows;
h = h₀ + vt - ¹/₂gt²
h = 8 + 48t - ¹/₂(32)t²
h = 8 + 48t - 16t²
<h3>Time for the ball to hit the ground</h3>
0 = 8 + 48t - 16t²
solve the above quadratic equation with formula method;
a = -16, b = 48, c = 8
t = 3.15 s
<h3>Time for the ball to be 56 ft above the ground</h3>
- let upward motion be positive
h = 8 + 48t + 16t²
56 = 8 + 48t + 16t²
0 = -48 + 48t + 16t²
solve the above quadratic equation with formula method;
a = 16, b = 48, c = -48
t = 0.79 s
Learn more about equation of motion here: brainly.com/question/25951773
#SPJ1
1950000 we know that 1 hg equal to 1000cg so 1000x195= 1950000
The third side is 84 inches long, therefore it has to be the hypotenuse because it's the longest side.
60 whatever unit it needs.
