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Nezavi [6.7K]
3 years ago
10

Use the distributive property to remove the parenthesis (x+7)8

Mathematics
2 answers:
dimaraw [331]3 years ago
5 0
8x+56

8(x)+8(7)= 8x+56
Luba_88 [7]3 years ago
3 0
(x+7)8 = 8x+56
The answer on the other side of the equation is the problem undistributed. 
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Which of the following place value tables shows 40,833?
jolli1 [7]

40,833 has...

4 Ten Thousands

8 Hundreds

3 Tens

3 Ones

6 0
3 years ago
Subtract whole number estimate.then find the difference estimate 428,734 -175,842
diamong [38]

You are estimating each into whole numbers. They are already whole numbers, and so just subtract.

428,734 - 175,842 = 252892

252,892 is your answer

hope this helps

3 0
3 years ago
Can someone please help me with this trigonometry problem. I would highly appreciate it if you did​
dexar [7]

Answer:

x ≈ 16.52

Step-by-step explanation:

Use the tangent ratio in the right triangle to find x

tan36° = \frac{opposite}{adjacent} = \frac{12}{x}

Multiply both sides by x

x × tan36° = 12 ( divide both sides by tan36° )

x = 12 / tan36° ≈ 16.52 ( to 2 dec. places )

5 0
3 years ago
For what values (cases) of the variables the expression does not exist: a a 2x−4
Natasha2012 [34]

Step-by-step explanation:

When the denominator is zero, the expression is undefined

2x-4=0

2x=4

x=2

5 0
3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
3 years ago
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