Answer:
look at this
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Step-by-step explanation:
MATH-WAY
It is SAS
Answer
3,4,5,5,6,7,7,7,7
Let . Then for all , so is strictly increasing. As , , so is bounded above by 1. This is to say,
and the integral of converges over the same domain, so this integral must also converge by comparison.
We have, by setting ,