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Colt1911 [192]
4 years ago
6

Janice has a "jammed" key on her keyboard. Every time she strikes the "S" key it sticks and doesn't pop back. What should Janice

use to fix the key?
a
Canned air

b
Screwdriver

c
Toothbrush

d
Wet cloth
Computers and Technology
2 answers:
Mice21 [21]4 years ago
4 0

Answer:

D.Wet cloth

Explanation:

Alekssandra [29.7K]4 years ago
3 0

Answer:

I think its A canned air

Explanation:

because i was in computer last year and finished with a 97 i hope this helps

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Write two example use of relationships ICT
Yakvenalex [24]

Answer:

Read it all before you write if this isn't what you searching for I'm sorry...:(

A relationship, in the context of databases, is a situation that exists between two relational database tables when one table has a foreign key that references the primary key of the other table. Relationships allow relational databases to split and store data in different tables, while linking disparate data items.

For example, in a bank database a CUSTOMER_MASTER table stores customer data with a primary key column named CUSTOMER_ID; it also stores customer data in an ACCOUNTS_MASTER table, which holds information about various bank accounts and associated customers. To link these two tables and determine customer and bank account information, a corresponding CUSTOMER_ID column must be inserted in the ACCOUNTS_MASTER table, referencing existing customer IDs from the CUSTOMER_MASTER table. In this case, the ACCOUNTS_MASTER table’s CUSTOMER_ID column is a foreign key that references a column with the same name in the CUSTOMER_MASTER table. This is an example of a relationship between the two tables.

3 0
3 years ago
A group of N stations share a 56-kbps pure ALOHA channel. Each station outputs a 1000-bit frame on average once every 100 sec, e
Sunny_sXe [5.5K]

Explanation:

Here, in the given statement, maximum flow capacity of the ALOHA channel = 18.4% = 0.184

Then, the stations N share 56 kbps

And, the channel rate = 0.184*56 = 10.304 kbps.  

Then, the outputs of the wach stations is 1000-bit frames/100 sec

\therefore, the output of the bits/ sec by each stations = \frac{1000}{100} bits/sec = 10 bits/sec

So, The output of the N stations is 10 bits/sec on the channel that having 10.304kb/sec

Finally, N = \frac{(10.304 \times 10^{3})}{10} = 1030 stations

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3 years ago
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