Answer:
I think it's C. but not a 100%
Answer:
long power(int i)
{
return pow(2,i);
}
Explanation:
The above written function is in C++.It does not uses loop.It's return type is long.It uses the function pow that is present in the math library of the c++.It takes two arguments return the result as first argument raised to the power of second.
for ex:-
pow(3,2);
It means 3^2 and it will return 9.
Answer:
B. Use a new support manager permission sets
Explanation:
According to the requirements, field level security is required so, 1st options is not suitable because it may reduce the maintenance cost but increase the risk of security.
By creating a separate page for each of the two, it will leads to increase in the maintenance cost of the system. So <u>Option C</u> is also not suitable.
Option B is more Suitable as compared to others, that <em>Create a new support manager permission set</em>, with the help of this, both of Support rep and Support manager can visualize their required information with the help of support manager permission. This solution will not compromise the security and not increase the maintenance cost.
Please note that the Problem to be solved from Protocol 1 is not provided hence the general answers. To construct and send, open a network environment a single multi-packet message, simply click "Add Packet" and then click "Send at Once".
<h3>How will the receiver know the order of the packets or if any are missing?</h3>
If the text or message sent does not make any reading sense, or if certain words are jumbled and out of place, then it is clear that something is wrong.
If the messages arrive in a coherent fashion, then the packet was fully received.
<h3>How will the receiver request missed packets and what will the sender do in response?</h3>
Where the users are familiar with the Transmission Control Protocol, lost packets can be detected when there is a timeout. Lost packets are referred to as Dropped packets.
Learn more about Packets at:
brainly.com/question/17777733
// making the class
class Counter {
int counter;
int limit;
// Constructor
Counter(int a, int b){
counter = a;
limit = b;
}
// static function to increment
static increment(){
if(counter<limit)
nCounter+=1;
}
// Decrement function
void decrement(){
if(counter>0)
nCounter-=1;
}
int getValue(){
return counter;
}
static int nCounter;
int getNCounters(){
return nCounter;
}
};
// Initializa the static
int Counter::nCounter = 0;
