Question

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x =

Answer 1

The answer to your problem is x=4/3 

Answer 2

Answer:

The positive solution to the given quadratic equation is given by:

                        $x=1.39$

Step-by-step explanation:

The quadratic equation is given by:

              $2x^2+3x-8=0$

We know that the solution of the quadratic equation of the type:

                     $ax^2+bx+c=0$

is given by:

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here,

$a=2,\ b=3\ and\ c=-8$

Hence, the solution is:

$x=\dfrac{-3\pm \sqrt{3^2-4\times 2\times (-8)}}{2\times 2}\\\\x=\dfrac{-3\pm \sqrt{9+64}}{4}\\\\x=\dfrac{-3\pm \sqrt{73}}{4}\\\\x=\dfrac{-3+\sqrt{73}}{4}\ or\ x=\dfrac{-3-\sqrt{73}}{4}\\\\x=1.38600\ or\ x=-2.88600$

which on rounding to the nearest  hundredth is:

$x=1.39\ \ or\ \ x=-2.89$

Hence, the positive solution is:

        $x=1.39$