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Nastasia [14]
3 years ago
5

How many degrees would you need to rotate a figure for the image to coincide with the pre-image?

Mathematics
1 answer:
Olegator [25]3 years ago
4 0
Hi there!

You would need to rotate an image 360 degrees for the figure out image to coincide with the previous image.

For example, if I rotated a triangle 360 degrees, it would be in the same place as it was before.

Hope this helps!
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9966 [12]

Answer:

$2.75

Step-by-step explanation:

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True or False? A secant is a line or segment that passes through a point on the circle and the center of the circle.
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Thr answer is False
That line is called diameter
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Find three numbers such that their sum is 12, the sum of the first, twice the second, and three times the third is 31, and the s
Tpy6a [65]

Answer:

a = 3, b = -1, c = 10

Step-by-step explanation:

Let the three numbers be a, b and c.

Equation 1: a + b + c = 12

Equation 2: a + 2b + 3c = 31

Equation 3: 9b + c = 1

Equation 2 - Equation 1:

Equation 4: b + 2c = 19

Equation 3 times by the number 2

Equation 5: 18b + 2c = 2

Equation 5 - Equation 4

17b = -17

b = -1

Substitute into Equation 4:

2c - 1 = 19

2c = 20

c = 10

Substitute into Equation 1:

a + b + c = 12

a - 1 + 10 = 12

a = 3

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3 years ago
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3 years ago
Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.
TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

(x-2)\\ (x-3)\\ (x-5)

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

x=2\\ x=3\\ x=5

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0

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the answer Part b) is

the cubic polynomial function is equal to

x^{3}-10x^{2} +31x-30=0

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