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Nastasia [14]
3 years ago
5

How many degrees would you need to rotate a figure for the image to coincide with the pre-image?

Mathematics
1 answer:
Olegator [25]3 years ago
4 0
Hi there!

You would need to rotate an image 360 degrees for the figure out image to coincide with the previous image.

For example, if I rotated a triangle 360 degrees, it would be in the same place as it was before.

Hope this helps!
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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9​
Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0
2 years ago
God please help me plz
Nat2105 [25]
You convert 432 sq inches into inches so 20.7846. Then you times that by 6. The answer is 124.7076 and if rounded 124.7
8 0
3 years ago
Pls answer this i want to know ok ok ok ok ok
bogdanovich [222]

Step-by-step explanation:

given \\ (x +  \frac{1}{x} ) = 7 \\ now \\ (x +  \frac{1}{x} ) ^{2}   \\ (7) ^{2} (given) \\ 49 \\ again \\  {x}^{2}  + ( \frac{1}{x} ) ^{2}  \\ (x  +   \frac{1}{x}) ^{2}  - 2 \times x \times  \frac{1}{x}  \\ (7) ^{2}  - 2 \\ 49 - 2 \\ 47

6 0
3 years ago
What dose No mean in math
Wewaii [24]

Answer:

Nobelium

Step-by-step explanation:

That looks like a chemistry element unless No is meaning the abbreviation No. - Meaning, number.

7 0
3 years ago
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