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Nastasia [14]
3 years ago
5

How many degrees would you need to rotate a figure for the image to coincide with the pre-image?

Mathematics
1 answer:
Olegator [25]3 years ago
4 0
Hi there!

You would need to rotate an image 360 degrees for the figure out image to coincide with the previous image.

For example, if I rotated a triangle 360 degrees, it would be in the same place as it was before.

Hope this helps!
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A Crayon is shown here.
Aleks04 [339]

The volume of the single crayon is 89.5 cm³, then the total volume of the crayons will be 2148 cm³. Then the correct option is D.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

A Crayon is shown here.

There are 24 crayons in a box.

The approximate total volume of the crayons will be

Total Volume of crayons = 24 × volume of the single crayon

The crayon is the combination of the cone and the cylinder

Then the volume of the single crayon (V₁) will be

\rm V_1 = \left ( \dfrac{1}{3} \times \pi \times r^2 \times h  \right ) + \left (  \pi \times r^2 \times h  \right )\\\\\rm V_1 = \left ( \dfrac{1}{3} \times \pi \times 1.5^2 \times 2  \right ) + \left (  \pi \times 1.5^2 \times 12  \right )\\\\V_1 = 4.712 + 84.82\\\\V_1 = 89.535 \approx 89.5

Then the Total volume will be

Total volume = 24 × 89.5

Total volume = 2148 cm³

More about the geometry link is given below.

brainly.com/question/7558603

#SPJ1

3 0
2 years ago
Find the sum of 7a^3 + 14a +12 and -6a^3 +12a^2 -7
SOVA2 [1]
To find the sum:

{7a}^{3} + 14a + 12  + ( {- 6a }^{3} ) + {12a }^{2}   - 7 \\  = {7a }^{3}   -  {6a}^{3}  + {12a }^{2}  + 14a + 12 - 7 \\  =  {a}^{3}  + {12a }^{2}  + 14a + 5
Therefore the answer is a^3+12a^2+14a+5.
Hope it helps!
8 0
4 years ago
Read 2 more answers
The value of the function at x=-6 is ?
Sholpan [36]

Answer:  x = 6, the y - coordinate is 4, therefore the value of the function when x = 6 is 4.

7 0
3 years ago
The actual length of c in the triangle shown is 15 cm.
Strike441 [17]
The answer is B. Hope this helps!
4 0
3 years ago
Read 2 more answers
?? So lost with this
labwork [276]

Answer:

A)\ 1,\ -1,\ -3\\\\B)\ d=-2\\\\C)\ \left\{\begin{array}{ccc}a_1=11\\a_n=a_{n-1}-2\end{array}\right\\\\D)\ f(n)=-2n+13

Step-by-step explanation:

It's an arithmetic sequence.

9 = 11 - 2

7 = 9 - 2

5 = 7 - 2

3 = 5 - 2

A) next three terms: 3 - 2 = 1, 1 - 2 = -1, -1 - 2 = -3

B) Common difference = -2

C) Recursive Function:

\left\{\begin{array}{ccc}a_1=11\\a_n=a_{n-1}-2\end{array}\right

D) Explicit Function:

f(n)=a_1+(n-1)d

a₁ - first term

d - common difference

Substitute a₁ = 11 and d = -2:

f(n)=11+(n-1)(-2)=11-2n+2=-2n+13

4 0
3 years ago
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