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Alenkasestr [34]
2 years ago
10

Sam wants to buy 8 pencils and 6 pens, which cost a total of $8.50. He realizes he doesn't have enough cash and instead takes on

ly 4 of each, which costs only $5. What is the price of each pen and pencil?
A. pen, $0.75; pencil, $0.50
B. pen, $0.50; pencil, $0.25
C. pen, $1.00; pencil, $0.25
D. pen, $0.80; pencil, $0.35
E. pen, $1.20; pencil, $0.25
Mathematics
2 answers:
ikadub [295]2 years ago
8 0

Answer:

A. pen, $0.75; pencil, $0.50.

step-by-step explanation: .75x4=$3.00. .50x4=$2.00 . $3.00+$2.00=$5.00



Reptile [31]2 years ago
6 0

Answer:

A. pen, $0.75; pencil, $0.50

Step-by-step explanation:

let pen be $x n pencil be $y

8 pencils and 6 pens cost a total of $8.50

(1) 8y + 6x = 8.5

4 of each cost $5

(2) 4y + 4x = 5

multiply (2) by 2:  8y + 8x = 10

subtract (1) from (2)x2:  8x - 6x = 10 - 8.5

2x = 1.5

x = 0.75

put back in (1):  8y + 6*0.75 = 8.5

8y = 8.5 - 4.5 = 4

y = 0.5

ans is A. pen, $0.75; pencil, $0.50

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\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{2}{4})

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​

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​2

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​​   to  \frac{1}{2}

​2

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​1

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\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{1}{2})

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MakcuM [25]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

p_v =2*P(Z>0.500)=0.617  

So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

Step-by-step explanation:

Data given and notation  

X_{1}=25 represent the number of homeowners who would buy the security system

X_{2}=9 represent the number of renters who would buy the security system

n_{1}=140 sample 1

n_{2}=60 sample 2

p_{1}=\frac{25}{140}=0.179 represent the proportion of homeowners who would buy the security system

p_{2}=\frac{9}{60}= 0.15 represent the proportion of renters who would buy the security system

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p_v represent the value for the test (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17  

Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500  

Statistical decision

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So the p value is a very low value and using any significance level for example \alpha=0.05, 0,1,0.15 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.  

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