Let a, ß be the roots of x² + 2ax + b =0.......[1]
⇒a + ß = -2a and aß = b
By hypothesis
la-ß | ≤ 2m
⇒ (a-ß)² ≤ 4m²
⇒ (a+ß)²-4aß < 4m²
⇒ 4a²-4b ≤ 4m²
⇒a² - b ≤ m²......(2)
And discriminant of (1) is >0
⇒4a²-4b> 0
⇒ b <a²...... (3)
From (2) and (3)
a² > b≥ (a² - m²)
b = [a² - m², a²)
The answer is 4 because 4*4=16
Answer:
the answer is c
Step-by-step explanation:
Add all the like terms
3b + b = b(3 + 1) = 4b
So, 3b + b + 6 = 4b + 6
