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VMariaS [17]
3 years ago
6

A local cinema allows customer to make a movie ticket reservation. A customer can be

Computers and Technology
1 answer:
MrRa [10]3 years ago
7 0
In cinema, people usually purchase a ticket after, they pay money for a certain show. So based on that we can design the software system like below to store each transaction that has details about purchaser of ticket, show details and so on.
Transactions: Class used to create transaction in a cinema hall 

Attribute:-

Name: Name of person Age:

Age of Person

Phone Number: Phone number

Email: email of person

customer_type: type of customer (can be ordinary or privilege)

room_type: type of customer (can be ordinary customer_type normal else luxurious)

date: transaction date

payment_mode: Transaction can be either done in cash or credit amount: amount of ticket

ticket_time: time of show
methods:
create_transaction(name, phone, email,  date, payment_mode, amount, ticket_time): creates a history of a transaction after a ticket has been purchased
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IrinaK [193]

Answer:

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Updates help patch security flaws. Hackers love security flaws, also known as software vulnerabilities. ...

Software updates help protect your data. ...

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Explanation:

hope that worked

3 0
3 years ago
A method to accept the number of drawers in the desk as input from the key board. This method returns the number of drawers to t
Julli [10]

Answer:

Following code takes the information about the wood from the user, do the process of calculating the value according to there type and numbers, then add the surcharge to it while giving the answer to the user.

For differentiating the type of woof i used the if then else statement while i used switch case statement for assigning the appropriate value according to the types of the wood will be processing in the program.

The code is given below:

Explanation:

Code:

namespace std;\\ any name instead of std.

{

   class Program

   { \\ starting the main program

       static void Main(string[ ] args)

       {

           int numberOfDrawers = 0;

           string deskWoodType = "o";

           double cost = 0;

           drawersMeth(numberOfDrawers);

           woodTypeMeth(deskWoodType);

           CalculateCostMeth(numberOfDrawers, cost, deskWoodType);

           OutPutCostMeth(deskWoodType , cost, numberOfDrawers);

       }//end main

       private static void drawersMeth(int numberOfDrawers)

       {

           int numOfDrawers;

           Console.WriteLine("Enter the number of desk drawers");

           numOfDrawers = Convert.ToInt16(Console.ReadLine());

           numberOfDrawers = numOfDrawers;

       }//end drawersMeth

       private static string woodTypeMeth(string deskWoodType)

       {

           Console.WriteLine("Enter the desk wood type. (eg. type mahogany, oak, or pine)");

           deskWoodType = Convert.ToString(Console.ReadLine());

           switch (deskWoodType)

           {

               case "mahogany":

                   {

                       deskWoodType = "m";

                       break;

                   }

               case "oak":

                   {

                       deskWoodType = "o";

                       break;

                   }

               case "pine":

                   {

                       deskWoodType = "p";

                       break;

                   }

               default:

                   {

                       deskWoodType = "error";

                       break;

                   }

           }

           return deskWoodType;

       }// end woodTypeMeth

       private static int CalculateCostMeth(string deskWoodType, int numberOfDrawers, int cost)

       {

           int pine = 100;

           int oak = 140;

           int other = 180;

           int surchage = 30;

           if (deskWoodType == "p")

               cost = surchage + (numberOfDrawers *pine );

           else if (deskWoodType == "o")

               cost = surchage + (numberOfDrawers *oak );

           else

               cost = surchage + (numberOfDrawers *other );

           return cost;

       }// end CalculateCostMeth

       private static void OutPutCostMeth(int numberOfDrawers, string deskWoodType, int cost)

       {

           double totalCost = cost;

           Console.WriteLine("The number of drawers is {0}", numberOfDrawers);

           Console.WriteLine("The wood finish you have selected is ", deskWoodType);

           Console.WriteLine("The total cost is {0}", totalCost);

       }//end outputCost

   }//end class

}//end nameSpace

5 0
3 years ago
The technique of ________ uses three columns that allows the entrepreneur to weigh both the advantages and the disadvantages of
Mekhanik [1.2K]
Force-field analysis
5 0
3 years ago
Role of computers in everyday life​
Simora [160]

Answer:

In modern word everything around us like GPS, ATM machines, cell phones, petrol pumps, portable play stations and all other modern devices use computer controlling units to conduct their featured operations. Surely computers have very elaborated role in daily day life of humans.

Explanation:

hope it helps thxs

8 0
3 years ago
write an assembly language procedure that also performs the binary search. The C program will time multiple searches performed b
laiz [17]

Answer:

Let’s identify variables needed for this program.

First variables will be the one which will hold the values present in the Given Numbers in Array list and key of 16-bit and it will be array ARR and KEY. variables will be holding the Messages MSG1 “KEY IS FOUND AT “, RES ”  POSITION”, 13, 10,” $” and MSG2 ‘KEY NOT FOUND!!!.$’ to be printed for the User. Other variables will be holding Length of the Array and it will be LEN, So in all Six variables.

The identified variables are ARR, KEY, LEN, RES, MSG1 and MSG2.

DATA SEGMENT

    ARR DW 0000H,1111H,2222H,3333H,4444H,5555H,6666H,7777H,8888H,9999H

    LEN DW ($-ARR)/2

    KEY EQU 7777H

    MSG1 DB "KEY IS FOUND AT "

    RES DB "  POSITION",13,10," $"

    MSG2 DB 'KEY NOT FOUND!!!.$'

DATA ENDS

CODE SEGMENT  

   ASSUME DS:DATA CS:CODE

START:

     MOV AX,DATA

     MOV DS,AX

   

     MOV BX,00

     MOV DX,LEN

     MOV CX,KEY

AGAIN: CMP BX,DX

      JA FAIL

      MOV AX,BX

      ADD AX,DX

      SHR AX,1

      MOV SI,AX

      ADD SI,SI

      CMP CX,ARR[SI]

      JAE BIG

      DEC AX

      MOV DX,AX

      JMP AGAIN

BIG:   JE SUCCESS

      INC AX

      MOV BX,AX

      JMP AGAIN

SUCCESS: ADD AL,01

        ADD AL,'0'

        MOV RES,AL

        LEA DX,MSG1

        JMP DISP

FAIL: LEA DX,MSG2

DISP: MOV AH,09H

     INT 21H

     

     MOV AH,4CH

     INT 21H      

CODE ENDS

END START

In this Assembly Language Programming, A single program is divided into four Segments which are 1. Data Segment, 2. Code Segment, 3. Stack Segment, and 4. Extra  Segment. Now, from these one is compulsory i.e. Code Segment if at all you don’t need variable(s) for your program.if you need variable(s) for your program you will need two Segments i.e. Code Segment and Data Segment.

Explanation:

The attached Logic is a C like Program to conduct a binary search we need small Algorithm Shown above in a very simple way, So Just we will covert the logic into Assembly There are many things uncommon in the programing Language. There are No While Loops or Modules but this things are to be implemented in different ways.

6 0
3 years ago
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