The average rate of change of f(x) from x = 5 to x = 8 would be gotten by; B: Substituting 5 for x and 8 for h in the expression x + one-half h + 15
<h3>How to used difference quotient to find average rate of change?</h3>
The difference quotient is defined as a measure of the average rate of change of a function over an interval.
The limit of the difference quotient which is the derivative is the instantaneous rate of change.
This differential quotient in calculus is usually expressed as;
[f(x + h) - f(x)]/h
We are given the differential quotient as;
f(x) = x + ¹/₂h + 15
Thus, the average rate of change of f(x) from x = 5 to x = 8 would be gotten by;
Substituting 5 for x and 8 for h in the expression x + one-half h + 15
Read more about Difference quotient at; brainly.com/question/18232053
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Answer:
yuhhhh
Step-by-step explanation:
except im grounded... but will def save this for 2 mounths
Factor 4 out of 4x+20.
4(x+5)
Puedes ser mas especico pir favor
A= 7843/324b. i think it might be that, not so sure
