Question

The function f is given by

Answer 1

Answer:

d. -22

Step-by-step explanation:

If F(x) is given by:

$f(x)=(x^{3}+bx+6) g(x)$

The derivative is given by:

$f'(x)=(3x^{2}+b) g(x)+(x^{3}+bx+6) g'(x)$

if f'(2)=0

$f'(2)=(3(2)^{2}+b) g(2)+((2)^{3}+2b+6) g'(2)=0$

$3(12+b)-(14+2b)=0$

$36+3b-14-2b=0$

$b=-22$