Answer:
The height of the second cone is 2 <em>h</em>₁.
Step-by-step explanation:
The volume of a cone is:
The volume of the first cone is, <em>V</em>₁ = 5 in³.
The volume of the second cone is, <em>V</em>₂ = 10 in³.
The two cones have the same base diameters.
This implies that the two radii are same, i.e. <em>r</em>₁ = <em>r</em>₂.
Compute the height of the second cone as follows:
Thus, the height of the second cone is 2 <em>h</em>₁.
A) as the exponent decreases by one, the number is divided by 5
B) as the exponent decreases by one, the number is divided by 4
C) as the exponent decreases by one, the number is divided by 3
D) 4⁰ = 4 ÷ 4 = 1
4⁻¹ = 1 ÷ 4 =
4⁻² = ÷ 4 =
E) 3⁰ = 3 ÷ 3 = 1
3⁻¹ = 1 ÷ 3 =
3⁻² = ÷ 3 =
Answer:
2.3 degrees.
Step-by-step explanation:
Please find the attachment.
We are told that an airplane must clear a 60-foot pole at the end of a runway 500 yards long.
Let us convert 500 yards to feet.
1 yard= 3 feet.
500 yards= 3*500 feet= 1500 feet.
We can see from our attachment pole and runway are in form of a right triangle. The pole is opposite to angle of elevation of plane and length of runway is adjacent.
Since tangent represents the relation between opposite and adjacent of right triangle, So we will use tangent to find angle of elevation that plane must ascend to clear the pole.
Therefore, the airplane must ascend 2.3 degrees to clear the pole.
