Solution:
we are given that
Jack planted 1 1/4 rows of lettuce in the family garden.
Rose planted 1 1/2 rows of broccoli and Calvin planted 4 5/12 rows of beans.
we have been asked to find -How many rows were planted in the garden?
To find this , we will add all the numbers of rows planted.
Hence number of rows planted
Answer:
The distribution is skewed, so use the five-number summary. range: 38, median: 16, half of the data are between 9.5 and 25
Step-by-step explanation:
In the picture attached the histogram is shown. We can see that data is skewed to the right, so we have to use the five-number summary. The range of the data is 39 - 1 = 38 (subtraction of the maximum value to the minimum value); the median is (15 + 17)/2 = 16 (if you order the values, 15 and 17 are in the middle); quartile 1 is 9.25 and quartile 3 is 25.5 (see diagram of box and whisker attached), then half of the data are between those values.
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
And margin of error (ME) of the mean can be calculated using the formula
ME= where
Thus, ME= ≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5