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3 years ago

Find y and x values please

Mathematics

1 answer:

Aleonysh [2.5K]3 years ago

3 0

(-2,6) iissssssss the answer

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Joy has ₱500.00 to spend for food. She spent ₱98.75 on Monday, ₱73.75 on Tuesday and ₱50.25 on Wednesday. How much money was lef

Alex787 [66]

Answer:

₱277.25

Step-by-step explanation:

₱500.00 - ₱98.75 - ₱73.75 - ₱50.25 = ₱277.25

8 0

3 years ago

Each member of the swim team must pay $76 to join the team. There are 376 members. How much does the team receive in dues?

Basile [38]

Answer:

$28,576

Step-by-step explanation:

$76 (amount that each member pays) * 376 (total members) = $28,576 (amount that will be received in dues)

I hope this helps :)

7 0

3 years ago

Please help asap plz

butalik [34]

Answer:

im think its 20 and 39 im not sure tho

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The school cafeteria serves tacos every 60 and cheeseburgers every eighth day.If tacos and cheeseburgers are both on today's men

Ad libitum [116K]

Answer:

120 days

Step-by-step explanation:

Tacos are served every 60 days.

Cheeseburgers are served every 8 days.

Since, both Cheeseburgers and Tacos are served today, the next day on which both will be served is gotten by finding the Lowest Common Multiple of 60 and 8.

To find the LCM,

First, we express the numbers as a product of their prime factors.

60= 2X2X3X5=2²X3X5

8=2X2X2=2³

Next, we take each of the term with the highest power and multiply.

L.C.M = 2³X3X5=120

After 120 days, Cheeseburgers and Tacos will be served on the same day.

5 0

3 years ago

Which expression is equivalent to (x superscript four-thirds baseline x superscript two-thirds Baseline ) superscript one-third

Andrei [34K]

<h3>The equivalent expression is:</h3>

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Solution:

Given expression is:

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}}$

We have to find the equivalent expression

We can simplify the above expression using law of exponents

Use the following law of exponents:

$a^m \times a^n = a^{m+n}$

Therefore,

$\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}+\frac{2}{3}})^{\frac{1}{3}}\\\\Simplify\\\\\displaystyle (x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = (x^2)^\frac{1}{3}$

Use another law of exponent

$(a^m)^n = a^{mn}$

Therefore,

$(x^{\frac{4}{3}}x^{\frac{2}{3}})^{\frac{1}{3}} = x^{\frac{2}{3}$

Thus the equivalent expression is found

5 0

3 years ago

Read 2 more answers