All categories

3 years ago

X/9 -1=5 X=? 9y+1=7 Y=? 3z/7 + 3=-7 Z=

Mathematics

2 answers:

AysviL [449]3 years ago

6 0

X/9 -1=5
X=?

9y+1=7
Y=?

3z/7 + 3=-7
Z=
X=54
Y=1/3
Z=-23 1/3

rjkz [21]3 years ago

5 0

x/9 -1 = 5

add 1 to both side of the equation

x/9 = 6

multiply both side of the equation by 9

x = 54

9y + 1 = 7

subtract 1 from each side of the equation

9y = 6

divide both side of the equation by 9

y = $\frac{6}{9}$

divide the numerator and the denominator by 3 in order to simplify your fraction

y = $\frac{2}{3}$

3z/7 + 3 = -7

subtract 3 from each side of the equation

3z/7 = -10

multiply both side of the equation by 7

3z = -70

divide both side of the equation by 3

z = $\frac{-70}{3}$

There you go! I really hope this helped, if there's anything just let me know! :)

You might be interested in

Danielle stayed in three different cities (Washington, D.C., Atlanta, Georgia, and Dallas, Texas) for a total of 22 nights. She

ziro4ka [17]

Answer:

do you know how to count

Step-by-step explanation:

you had putten 5 cities not 3

4 0

3 years ago

2 Points

vfiekz [6]

Answer:

$63

Step-by-step explanation:

Penny = $0,01
Nickel = $0.05
Dime = $0.1
Quarter= $0.25

Number of pennies = 6*50 = 300
Number of nickels = 5*40= 200
Number of dimes = 4*50= 200
Number of quarters = 3*40 = 120

<u>Total amount of money:</u>

300*0.01+ 200*0.05 + 200*0.1 + 120*0.25 = $63

5 0

3 years ago

Read 2 more answers

How to find the vertex calculus 2What is the vertex, focus and directrix of x^2 = 6y

son4ous [18]

Solution:

Given:

$x^2=6y$

Part A:

The vertex of an up-down facing parabola of the form;

$\begin{gathered} y=ax^2+bx+c \\ is \\ x_v=-\frac{b}{2a} \end{gathered}$

Rewriting the equation given;

$\begin{gathered} 6y=x^2 \\ y=\frac{1}{6}x^2 \\ \\ \text{Hence,} \\ a=\frac{1}{6} \\ b=0 \\ c=0 \\ \\ \text{Hence,} \\ x_v=-\frac{b}{2a} \\ x_v=-\frac{0}{2(\frac{1}{6})} \\ x_v=0 \\ \\ _{} \\ \text{Substituting the value of x into y,} \\ y=\frac{1}{6}x^2 \\ y_v=\frac{1}{6}(0^2) \\ y_v=0 \\ \\ \text{Hence, the vertex is;} \\ (x_v,y_v)=(h,k)=(0,0) \end{gathered}$

Therefore, the vertex is (0,0)

Part B:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

$\begin{gathered} x^2=6y \\ 6y=x^2 \\ 4(\frac{3}{2})(y-k)=(x-h)^2 \\ \text{putting (h,k)=(0,0)} \\ 4(\frac{3}{2})(y-0)=(x-0)^2 \\ Comparing\text{to the standard form;} \\ p=\frac{3}{2} \end{gathered}$

Since the parabola is symmetric around the y-axis, the focus is a distance p from the center (0,0)

Hence,

$\begin{gathered} Focus\text{ is;} \\ (0,0+p) \\ =(0,0+\frac{3}{2}) \\ =(0,\frac{3}{2}) \end{gathered}$

Therefore, the focus is;

$(0,\frac{3}{2})$

Part C:

A parabola is the locus of points such that the distance to a point (the focus) equals the distance to a line (directrix)

Using the standard equation of a parabola;

$\begin{gathered} 4p(y-k)=(x-h)^2 \\ \\ \text{Where;} \\ (h,k)\text{ is the vertex} \\ |p|\text{ is the focal length} \end{gathered}$

Rewriting the equation in standard form,

Since the parabola is symmetric around the y-axis, the directrix is a line parallel to the x-axis at a distance p from the center (0,0).

Hence,

$\begin{gathered} Directrix\text{ is;} \\ y=0-p \\ y=0-\frac{3}{2} \\ y=-\frac{3}{2} \end{gathered}$

Therefore, the directrix is;

$y=-\frac{3}{2}$

3 0

1 year ago

Two numbers are in ratio s:t .if the first is a,find the second

Whitepunk [10]

Answer:

The second number is a*t/s

Step-by-step explanation:

s/t = a / x Let x be the second number.

sx = at divide by s

x = at/s

7 0

3 years ago

HELPPP frenss!!! HURRY j

Anastasy [175]

Answer:

(2, -7)

x = 2

y = -7

Step-by-step explanation:

Let's solve this system of equations by elimination.

Start by multiplying the first equation by 2:

$2(4x)+2(3y)=2(-13)\\8x+6y=-26$

Next, multiply the second equation by 3:

$3(-5x)+3(2y)=3(-24)\\-15x+6y=-72$

Notice that both equations now have a "6y", meaning we can subtract both equations and thereby eliminating the variable "y" from the equation:

$8x+6y-(-15x+6y)=-26-(-72)\\8x+6y+15x-6y=-26+72\\23x=46$

Divide both sides by 23

$x=2$

Substitute 2 for "x" to solve for "y".

$4x+3y=-13\\4(2)+3y=-13\\8+3y=-13$

Subtract 8 from both sides:

$3y=-21$

Divide both sides by 3:

$y=-7$

Therefore the answer is:

$(x, y)=(2, -7)$

Additional Comments:

Note that we can only divide, subtract, multiply, or add both sides of the equation by the same quantity due to the Division, Subtraction, Multiplication, or Addition Property of Equality. These properties state that if you divide/subtract/multiply/add one side of the equation by one quantity, you must do the same to the other side of the equation so that it remains an equation.

3 0

2 years ago