What is an equation of the line perpendicular to 5x−4y=10 5x−4y=10 that passes through the point (−1,−6) (−1,−6) ?
1 answer:
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Answer:
y = - 2x + 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m =
with (x₁, y₁ ) = (1, 4 ) and (x₂, y₂ ) = (2, 2 )
m = =
= - 2 , then
y = - 2x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (2, 2 ) , then
2 = - 4 + c ⇒ c = 2 + 4 = 6
y = - 2x + 6 ← equation of line