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Nataly_w [17]
3 years ago
11

Can someone please help me with this ASAP

Mathematics
2 answers:
agasfer [191]3 years ago
8 0

Answer:

D

Step-by-step explanation:

Kryger [21]3 years ago
4 0
D because three 20s of what’s half of 10 is 5 which makes 4. So three of what makes 20 evenly with the same number is 180.
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stepan [7]

Answer:

simplify question is 3a^2 +6a+9ab

Step-by-step explanation:

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3 years ago
Find the area of the regular polygon. Round your answer to the nearest tenth. 344.3 in.2 172.2 in.2 84.4 in.2 50.0 in.2
My name is Ann [436]
Area = \frac{a X p}{2}
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7 0
3 years ago
Samantha wants to use her savings of 1150 to buy shirts and watches for her family. The total price of the shirt she bought was
ioda

<u>Answer-</u>

<em>The maximum number of watches that Samantha come by with her savings is </em><em>10</em><em>.</em>

<u>Solution-</u>

The amount of money Samantha has in her savings account = $1150

She wants to buy shirts and watches.

Cost of one shirt = $84

Cost of each watch = $99

Let she can buy maximum of x watches, so the net price of the watches is $99x.

Then,

\Rightarrow 99x+84=1150\\\\\Rightarrow 99x=1150-84\\\\\Rightarrow 99x=1066\\\\\Rightarrow x=\dfrac{1066}{99}\\\\\Rightarrow x=10.77

As the number of watches can not be in fraction, so at most she can buy 10 watches.

8 0
3 years ago
8. Given triangle AXTB with x = 8, t = 11 and b = 14, what is the mZT?
Ber [7]
I need the answer aswell
5 0
3 years ago
A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.
denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let \mu = <u><em>population mean light bulb life.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 500 hours      {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, H_A : \mu < 500 hours     {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean bulb life = 490 hours

           σ = population standard deviation = 50 hours

           n = sample of light bulbs = 100

So, <u><em>the test statistics</em></u>  =  \frac{490-500}{\frac{50}{\sqrt{100} } }

                                     =  -2

The value of z test statistics is -2.

<u>Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.</u>

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis.</u>

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

7 0
3 years ago
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