1.) y+6=3(x+2) C
y+6=3x+6
y=3x+6-6
y=3x+6
2.) y=1/2(x+8)-2 B
y=1/2x+4-2
y=1/2x+2
3.) y+1=1(x-3) E
y+1=x-3
y=x-3-1
y=x-4
4.) -4x+y=-2 A
y=-4x-2
5.) 2x-4y=-4 F
-4y=-2x-4
y=-2/-4x-4/-4
y=2/4x+4/4
y=1/2x+1
6.) 2x+4y=8 D
4y=-2x+8
y=-2/4x+8/4
y=-1/2x+4/2
y=-1/2x+2
You did not give us the function
Answer:
Average Cost per game for 4 games is:
A) $4.75
Step-by-step explanation:
As the question is not complete, lets complete it first.
At the bowling Alley, shoe rentals cost $3 while a games costs $3. The expression that represents the average costs per game 'c' , in dollars, where n is the number of games, is:

To find average cost per game, for 4 games, simpli substitute n=4 into the given equation:

So Average Cost per game for 4 games is:
c = 4.75$
Least is on top, Greatest is on bottom
-33
5.67
32
509