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qaws [65]
4 years ago
7

Students are paired in teams for a group science project. The number of hours

Mathematics
1 answer:
inessss [21]4 years ago
6 0

Answer:

They spent 4 more hours.

Step-by-step explanation:

I added up Paloma's hours and Abdul's, 21 + 18 = 39! And then I added Ben's and Min's, 13 + 22 = 35! So then I subtract 39 - 35 = 4! yay!

If I got it right can I have Brainliest thanks!

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How does f(x) = 5x change over the interval from x = 7 to x = 8?
hichkok12 [17]

Answer:

the slope is 5

Step-by-step explanation:

f(x) = 5x

f(8) = 5(8) = 40    (8,40)

f(7) = 5*7 = 35 (  7,35)

the slope is 5


4 0
3 years ago
Read 2 more answers
The volume of a prism with side lengths measured in millimeters is 20. How could this measurement be written? Check all that app
Katyanochek1 [597]

The unit measurement of the a volume in mm is mm³(millimetres cube.)

<h3>How to find volume ?</h3>

Volume is is defined as the space occupied within the boundaries. The objects are usually solid objects.

The volume of a 3 dimensional figure is the product of the base area and the height.

Therefore, the units of volume is measured in cubic units.

The volume of a prism with side lengths measured in millimetres is 20.

Therefore, the measurement can be represented as follows:

20 mm³

learn more on volume here: brainly.com/question/16310824

#SPJ1

4 0
2 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
zhannawk [14.2K]

Answer:

y=27;y=−42

Step-by-step explanation:

33−y=6;63+y=21

y=27;y=−42

I hope this helps!

3 0
3 years ago
Read 2 more answers
Find the length of the curve. R(t) = 7t, 3 cos(t), 3 sin(t) , −2 ≤ t ≤ 2
Leviafan [203]

we are given

r(t)=(7t,3cos(t),3sin(t))

we can find x , y and z

x=7t,y=3cos(t),z=3sin(t))

now, we can use arc length formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

now, we can find derivative

x'=7,y'=-3sin(t),z'=3cos(t))

now, we can plug values

and we get

L=\int _{-2}^2\sqrt{7^2+\left(-3\sin \left(t\right)\right)^2+\left(3\cos \left(t\right)\right)^2}dt

L=\int _{-2}^2\sqrt{7^2+9}dt

=\sqrt{58}\cdot \:2-\left(-2\sqrt{58}\right)

L=4\sqrt{58}...........Answer


8 0
4 years ago
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