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alexandr1967 [171]
3 years ago
15

Set up a rational equation and then solve the following problems. A positive integer is twice another. The difference of the rec

iprocals of the two positive integers is 1/18. Find the two integers.
Mathematics
1 answer:
kupik [55]3 years ago
3 0

Answer:

9 and 18

Step-by-step explanation:

2x and x are the numbers

1/x-1/2x=1/18

2/2x-1/2x=1/18

1/2x=1/18

2x=18X=9,

2x=18

The two integers are 9 and 18

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Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression 2b+b and 3b and values of b as 1, 2 and 3.

Consider first expression that is, 2b+b.

Substituting the value of b=1,

2\left(1\right)+\left(1\right)=2+1=3 ....1

Substituting the value of b=2,

2\left(2\right)+\left(2\right)=4+2=6 ....2

Substituting the value of b=3,

2\left(3\right)+\left(3\right)=6+3=9 ....3

Consider second expression that is, 3b.

Substituting the value of b=1,

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Substituting the value of b=2,

3\left(2\right)=6 ....5

Substituting the value of b=3,

3\left(3\right)=9 ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

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