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allochka39001 [22]
3 years ago
12

How long did it take the water to completely drain?

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0
I can’t see the whole thing take a picture of it again or explain the problem to me
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the height of a tower is 15m more than tiwce the height of a building find the height of the building if tower is 255m tall​
PtichkaEL [24]

Answer: 120m

Step-by-step explanation:

Let the height of the building be represented by x.

Since the height of a tower is 15m more than tiwce the height of a building, the height of the tower will be:

= (2 × x) + 15

= 2x + 15

Since the tower is 255m tall, therefore,

2x + 15 = 255

2x = 255 - 15

2x = 240

x = 240/2

x = 120

The height of the building is 120m

3 0
3 years ago
Plz help, thank you!!!
dangina [55]
The slope should be 3/5 because the rise over run using the points (0,3) and (5,6) result in 3/5.
6 0
3 years ago
Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 4(m∠Y) − 210°. Find m∠Y.
EleoNora [17]

Answer:

angle Y= 60 degrees

Step-by-step explanation:

angle S + angle Y = 90 degrees because they are complementary

Y = 90 - S

angle S = 4(Y)-210

substitute for Y

S = 4(90 - S) - 210

S = 360 - 4S - 210

reduce

5S = 150

S = 30

Y = 90 - 30 = 60

4 0
3 years ago
A study by the Pew Research Center1 reports that in 2010, for the first time, more adults aged 18 to 29 got their news from the
sergejj [24]

Answer:

Null hypothesis:p \leq 0.65  

Alternative hypothesis:p > 0.65  

z=\frac{0.66 -0.65}{\sqrt{\frac{0.65(1-0.65)}{1500}}}=0.812  

p_v =2*P(z>0.812)=0.208  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion it's not significantly higher from 0.65.  

We don't have enough evidence to conclude that the true % it's higher than 65%, since we fail to reject the null hypothesis on this case.

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the adults that   said television was one of their main sources of news.

\hat p=0.66 estimated proportion of adults that said television was one of their main sources of news.

p_o=0.65 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is higher than 0.65:  

Null hypothesis:p \leq 0.65  

Alternative hypothesis:p > 0.65  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.66 -0.65}{\sqrt{\frac{0.65(1-0.65)}{1500}}}=0.812  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>0.812)=0.208  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion it's not significantly higher from 0.65.  

Do we find evidence that more than 65% of all US adults use television as one of their main sources for news?

We don't have enough evidence to conclude that the true % it's higher than 65%, since we fail to reject the null hypothesis on this case.

6 0
3 years ago
I like strawberries.
natali 33 [55]

Answer:

h

Step-by-step explanation:

5 0
3 years ago
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