Answer:
The length of AC is;
C. 50
Step-by-step explanation:
By the midpoint of a triangle theorem, we have that a segment that spans across and intersects with the midpoints of two sides of a triangle is equal to half the length of the third side and parallel to the length of the third side
The given parameters are;
The midpoints of ΔACE are B, D, and F
The length of EC = 44
The length of DF = 25
Therefore, we have;
Given that DF is a midsegment of triangle ΔACE, then DF ║ AC and
the length of DF = (1/2) × AC the length of AC
∴ The length of AC = 2 × The length of DF
The length of DF = 25
∴ The length of AC = 2 × 25 = 50
The length of AC = 50
The answer is 21x-28 hope it helps
We have
3 / (x-5) - x/5
We make the GCF and we have
15/[ 5(x-5) ] - x(x-5)/[ 5(x-5)]
= [ 15 - x(x-5) ] [5(x-5)]
= [ 15 - x^2 + 5x] / [ 5 (x-5) ]
= [15 - x^2 + 5x]/[5x - 25]
An answer to your question is (15-x^2+5x)/(5x-25)
Answer:
42.8 + or - 12
Step-by-step explanation:
He's either gaining or losing $12 so you can write 42.8 plus or minus 12 as the equation
