Question

The measure of angle A is 15°, and the length of side BC is 8. What are the lengths of the other two sides, rounded to the nearest tenth? AC =  AB = 

Answer 1

This is the concept of geometry, given that AB=AC, it means that the tirangle is isosceles, thus to get the value of AB and AC we proceed as follows;
thus using the cosine rule:
c^2=a^2+b^2-2abcosC
suppose\AB=AC=x
thus;
8^2=x^2+x^2-2*x*xcos15
64=2x^2-2x^2cos15

64=2x^2-1.9x^2
64=0.1x^2
x^2=640
x=sqrt640
x=25.3
hence;
AC=AB=25.3

Answer 2

AC = 29.9
AB = 30.9 

I just took it :)