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sasho [114]
3 years ago
5

Complete the rational operation

D%7B5%7D%20" id="TexFormula1" title=" \frac{3}{x - 5} - \frac{x}{5} " alt=" \frac{3}{x - 5} - \frac{x}{5} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
prisoha [69]3 years ago
6 0
We have
                             3 / (x-5) - x/5
We make the GCF and we have
                                    15/[ 5(x-5) ] - x(x-5)/[ 5(x-5)]
                                  = [ 15 - x(x-5) ]  [5(x-5)]
                                  = [ 15 - x^2 + 5x] / [ 5 (x-5) ]
                                  = [15 - x^2 + 5x]/[5x - 25]
An answer to your question is (15-x^2+5x)/(5x-25)
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Plz help me or i will literly start cying cuz i dont rly understand
Ann [662]

Answer: Its very simple to solve slopes

Step-by-step explanation:

All you need to do is to calculate the difference in the y coordinates of the 2 points and divide that by the difference of the x coordinates of the points(rise over run). That will give you the slope.

6 0
3 years ago
What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?
posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\

Since\  \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0

5 0
3 years ago
PLEASE HELP!!! Show your work too, please!
dimulka [17.4K]

Step-by-step explanation:

first fish tank: 95-4x

second fish tank: 40+5x

1. Define variable

The variable x represents the number of days.

2. Write the inequality

<em>95-4x=40+5x</em>

<em />

3. You probably don't need the answer but I am just going to solve.

The first fish tank will have less water than the second fish tank after 7 days.

<em>95-4x=40+5x </em>

<em>95-4(7)=40+5(7)</em>

<em>95-28=40+35</em>

<em>67=75</em>

<em>Since the first equation (95-4x) represents the first fish tank, and the second equation (40+5x) represents the second fish tank, the solution shows how the amount of water in the first fish tank is less than the amount of water un the second fish tank after 7 days.</em>

8 0
3 years ago
Read 2 more answers
In right-angled ∆ ABC, ∟B=90⁰. ∆ ABC is in the first and second quadrant on the graph paper. The coordinates of the points A and
Musya8 [376]

Answer:

The given coordinates of the points A and C of the right triangle ABC are (2, 5) and (-2, 3) respectively

The possible pairs of the coordinates of the point B are found as follows;

1) Draw a horizontal line from the point C to the right and a vertical line down from the point A to get the point B at (2, 3) which is the point of the perpendicular intersection of the two constructed lines above

2) Draw a vertical line from the point C upwards and a horizontal line to the left from the point A to get the point B at (-2, 5) which is the point of the  perpendicular intersection of the two newly constructed lines here

Step-by-step explanation:

3 0
3 years ago
If a snowball melts so that its surface area decreases at a rate of 9 cm2/min, find the rate (in cm/min) at which the diameter d
zhuklara [117]

Answer:

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

Step-by-step explanation:

Surface area of an snowball:

An snowball has spherical format. The surface area of an sphere is given by:

S = d^2\pi

In which d is the diameter of the sphere.

In this question:

We need to differentiate S implicitly in function of time. So

\frac{dS}{dt} = 2d\pi\frac{dd}{dt}

Surface area decreases at a rate of 9 cm2/min

This means that \frac{dS}{dt} = -9

At which the diameter decreases when the diameter is 10 cm?

This is \frac{dd}{dt} when d = 10. So

\frac{dS}{dt} = 2d\pi\frac{dd}{dt}

-9 = 2(10)\pi\frac{dd}{dt}

\frac{dd}{dt} = -\frac{9}{20\pi}

\frac{dd}{dt} = -0.143

Area in cm², so diameter in cm.

The diameter decreases at a rate of 0.143cm/min when it is of 10 cm.

8 0
3 years ago
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