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2 years ago

-138≥-6(6b-7)║ what is the value of b?

1 answer:

7 0

-138 ≥ -6(6b - 7)

Start by multiplying everything within the parentheses by -6.

-138 ≥ -36b + 42

Now move the +42 to the other side, so you're left with -36b. (You do this by subtracting 4242)

-138 - 42 ≥ -36b

-180 ≥ -36b

Divide both sides by -36 to find the value of b.

-180 / -36 ≥ b

5 ≥ b.

The answer is b ≤ 5.

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$H_{a} :u1>u2$

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Determine the hypothesis

$H_{0}:$ u1≤u2

$H_{a} :u1>u2$

find the degree of freedom $(\frac{s1^2}{n1} +\frac{s2^2}{n2} )^2/(\frac{s1^2}{n1} )^2/n1-1+(s2^2/n2)^2/n2-1\\\\(\frac{59.42^2}{16} +\frac{51.7476^2}{12} )^2/(\frac{59.42^2}{16} )^2/16-1+(51.74^2/12)^2/12-1$

p-value is the probability of obtaining the value of the test statistics. In the column of t-value in the row df=25

0.025<P<0.05

if the P value is actually less than or the same as the significant level, then the null hypothesis is rejected

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