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Butoxors [25]
3 years ago
15

Use completing the square to solve this quadratic equation x^2+10x+25=2

Mathematics
1 answer:
never [62]3 years ago
5 0

answer:

( x + 5 )^2 = 2

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Help help help please!!!!!!!!!!
Paul [167]

Answer:

{x}^{2}  + 2x + 1

Step-by-step explanation:

They ask: f(x) - g(x) =

( {x}^{2}  + 3x + 2) - (x + 1)

{x}^{2}  + 2x + 1

5 0
2 years ago
Find the missing side link when the area is 171 km².
polet [3.4K]

The missing side is 9km

7 0
3 years ago
Determine which of the lines, if any, are parallel. Explain.
MariettaO [177]

Answer:

Parallel lines have same slope but different y-intercept

None of the given equations have same slope. Therefore lines are not parallel.

Step-by-step explanation:

Slope of Line a: 4y +x=8 is -1/4

Slope of Line b: 2y + x = 4 is -1/2

Slope of Line c: 2y = -3x + 6 is -3/2

3 0
3 years ago
What the volume is of this solid
mrs_skeptik [129]

Answer:

336.

Step-by-step explanation:

8 x 7 x 6 = 336.

Feel free to let me know if you need more help! :)

5 0
2 years ago
What is the solution of x=2+ square root x-2?
alex41 [277]

So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

x-2=\sqrt{x-2}

Next, square both sides:

(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2

Next, subtract x and add 2 to both sides of the equation:

x^2-5x+6=0

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

x^2-2x-3x+6=0

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

x(x-2)-3(x-2)=0

Now you can rewrite the equation as (x-3)(x-2)=0

Now, apply the Zero Product Property and solve for x as such:

x-3=0\\x=3\\\\x-2=0\\x=2

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

8 0
3 years ago
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