Question

ASAP I NEED TO GRADUATE THIS WEEK

Answer 1

Answer:

Part 1) Option a. $240\ dices$

Part 2) Option c. $9.156.24\ pounds$

Step-by-step explanation:

Part 1)

step 1

Find the volume of one dice

The volume is equal to

$V=b^{3}$

we have

$b=2\ cm$

substitute

$V=2^{3}=8\ cm^{3}$

step 2

Find the volume of the box

The volume is equal to

$V=LWH$

we have

$L=20\ cm$

$W=12\ cm$

$H=8\ cm$

substitute

$V=20*12*8=1,920\ cm^{3}$

step 3

Find the number of dices

Divide the volume of the box by the volume of one dice

$1,920/8=240\ dices$

Part 2)

step 1

Find the volume of the cylinder

The volume is equal to

$V=\pi r^{2} h$

we have

$r=9\ ft$

$h=12\ ft$

assume

$\pi =3.14$

substitute

$V=(3.14)(9)^{2}(12)$

$V=3,052.08\ ft^{3}$

step 2

Find how many pounds of sand will fit into the cylinder

using proportion

$\frac{3}{1}\frac{pounds}{ft^{3}}=\frac{x}{3,052.08}\frac{pounds}{ft^{3}}\\ \\x=3,052.08*3\\ \\x=9.156.24\ pounds$