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2 years ago

7

In a line of students. Jenna is number 8. The teacher says that a rule for a number patter is add 4. The first student in line s

ays the first term is 7. What number Jenna say?

1 answer:

tatyana61 [14]2 years ago

7 0

She says 35 because number 7 in line says 31, so 31+4=35...

I hope this helped you!

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Lines ab and cd are parallel. If MN is 70° then what is my

fgiga [73]

The figure below is a parallelogram which statement must be true? D___________E | | |__________ | F G a.line Df is parallel to line de b. Line Df is parallel to line eg c. Line fg is parallel to line eg d. Line fg is parallel to line df 3. All __ are

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2 years ago

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. In the equation√n+5

Yuki888 [10]

Answer:

n = 59

Step-by-step explanation:

The given equation of n is $\sqrt{n + 5} - \sqrt{n - 10} = 1$ and we have to solve it for n.

$\sqrt{n + 5} - \sqrt{n - 10} = 1$ ........... (1)

⇒ $\frac{(n + 5) - (n - 10)}{\sqrt{n + 5} + \sqrt{n - 10}} = 1$

{Rationalizing the numerator}

⇒ $\sqrt{n + 5} + \sqrt{n - 10} = 15$ .............. (2)

Now, adding (1) and (2) we get

$2\sqrt{n + 5} = 16$

⇒ n + 5 = 64 {Squaring both sides}

⇒ n = 59 (Answer)

4 0

2 years ago

Please help me i don’t know if I’m right

Scilla [17]

Answer:

your choice is correct

Step-by-step explanation:

The magnitude of the difference between the target amount and the actual amount will be no greater than the allowed error.

|x -34| ≤ 0.25

5 0

2 years ago

Gianni was thinking about paying his mother back in less than 100 weeks if he pays his mother $20 a week how many week will it t

weeeeeb [17]

What is the total amount of money he owes back?

6 0

3 years ago

Read 2 more answers

Help. <br>Please its urgent show workings.<br>

laiz [17]

Answer:

see explanation

Step-by-step explanation:

There are 2 possible approaches to differentiating these.

Expand the factors and differentiate term by term, or

Use the product rule for differentiation.

I feel they are looking for use of product rule.

Given

y = f(x). g(x) , then

$\frac{dy}{dx}$ = f(x).g'(x) + g(x).f'(x) ← product rule

(a)

y = (2x - 1)(x + 4)²

f(x) = 2x - 1 ⇒ f'(x) = 2

g(x) = (x + 4)²

g'(x) = 2(x + 4) × $\frac{d}{dx}$ (x + 4) ← chain rule

= 2(x + 4) × 1

= 2(x + 4)

Then

$\frac{dy}{dx}$ = (2x - 1). 2(x + 4) + (x + 4)². 2

= 2(2x - 1)(x + 4) + 2(x + 4)² ← factor out 2(x + 4) from each term

= 2(x + 4) (2x - 1 + x + 4)

= 2(x + 4)(3x + 3) ← factor out 3

= 6(x + 4)(x + 1)

--------------------------------------------------------------------------

(b)

y = x(x² - 1)³

f(x) = x ⇒ f'(x) = 1

g(x) = (x² - 1)³

g'(x) = 3(x² - 1)² × $\frac{d}{dx}$ (x² - 1) ← chain rule

= 3(x² - 1)² × 2x

= 6x(x² - 1)²

Then

$\frac{dy}{dx}$ = x. 6x(x² - 1)² + (x² - 1)³. 1

= 6x²(x² - 1)² + (x² - 1)³ ← factor out (x² - 1)²

= (x² - 1)² (6x² + x² - 1)

= (x² - 1)²(7x² - 1)

----------------------------------------------------------------------

(c)

y = (x² - 1)(x³ + 1)

f(x) = x² - 1 ⇒ f'(x) = 2x

g(x) = (x³ + 1) ⇒ g'(x) = 3x²

Then

$\frac{dy}{dx}$ = (x² - 1). 3x² + (x³ + 1), 2x

= 3x²(x² - 1) + 2x(x³ + 1) ← factor out x

= x[3x(x² - 1) + 2(x³ + 1) ]

= x(3x³ - 3x + 2x³ + 2)

= x(5x³ - 3x + 2) ← distribute

= 5 $x^{4}$ - 3x² + 2x

--------------------------------------------------------------------

(d)

y = 3x³(x² + 4)²

f(x) = 3x³ ⇒ f'(x) = 9x²

g(x) = (x² + 4)²

g'(x) = 2(x² + 4) × $\frac{d}{dx}$ (x² + 4) ← chain rule

= 2(x² + 4) × 2x

= 4x(x² + 4)

Then

$\frac{dy}{dx}$ = 3x³. 4x(x² + 4) + (x² + 4)². 9x²

= 12 $x^{4}$ (x² + 4) + 9x²(x² + 4)² ← factor out 3x²(x² + 4)

= 3x²(x² + 4) [ 4x² + 3(x² + 4) ]

= 3x²(x² + 4)(4x² + 3x² + 12)

= 3x²(x² + 4)(7x² + 12)

5 0

2 years ago