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Marianna [84]
3 years ago
7

How does knowing the absolute value of an integer help in determining the distance of two ordered pairs?

Mathematics
1 answer:
Leviafan [203]3 years ago
6 0
Hey there!

The absolute value helps because when you the absolute value is the the distance of a number away from 0. Meaning that if your finding distance it will never be negative.

Finding the distance between the two is subtracting one of the numbers from each ordered pair from each other. Whether the number is negative or positive, you always turn it, or leave it into a positive number because distance is always positive.


Hope this helps !
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If 9(x-9)=-11 then x=?
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9(x-9)=-11\\
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x=\dfrac{70}{9}
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When writing a summary for a text or even after watching a movie, the summary will: Question 2 options: A.) Be shorter than the
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Answer:

D.) All the above answer choices are good characteristics of a summary.

Step-by-step explanation:

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Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take
Ipatiy [6.2K]

Answer:

a) r = 0.974

b) Critical value = 0.602

Step-by-step explanation:

Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below

Test A | 64 48 51 59 60 43 41 42 35 50 45

Test B |  91 68 80 92 91 67 65 67 56 78 71

To find - (a) What is the value of the linear coefficient r ?

             (b) Assuming a 0.05 level of significance, what is the critical value ?

Proof -

A)

r = 0.974

B)

Critical Values for the Correlation Coefficient

n       alpha = .05          alpha = .01

4           0.95                       0.99

5           0.878                     0.959

6           0.811                       0.917

7           0.754                      0.875

8           0.707                      0.834

9           0.666                      0.798

10          0.632                      0.765

11           0.602                      0.735

12          0.576                       0.708

13          0.553                       0.684

14           0.532                       0.661

So,

Critical r = 0.602 for n = 11 and alpha = 0.05

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lyudmila [28]
The answer is D hope this help

8 0
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As far as my math can tell the bigger one has a hypotnuse length of 8 whereas the smaller anes length is about 1 1/2
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