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Marianna [84]
3 years ago
7

How does knowing the absolute value of an integer help in determining the distance of two ordered pairs?

Mathematics
1 answer:
Leviafan [203]3 years ago
6 0
Hey there!

The absolute value helps because when you the absolute value is the the distance of a number away from 0. Meaning that if your finding distance it will never be negative.

Finding the distance between the two is subtracting one of the numbers from each ordered pair from each other. Whether the number is negative or positive, you always turn it, or leave it into a positive number because distance is always positive.


Hope this helps !
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468 divided by 4 which is 117
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Identify the terms of the expression. 3r^2+4r+8
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Answer:

The terms

Step-by-step explanation:

The terms in this expression are coefficients, constants, variables, and exponents. 3 and 4 would be the coefficients. 8 would be the constant. r is the variable and 2 is the exponent.

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Mr. Palmer deposited $850 into a simple interest account for 8 years, earning at an 8% interest rate. What will his total balanc
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Answer:

solution given:

principal [P]=$850

time[T]=8years

rate[R]=8%

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2 years ago
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i
USPshnik [31]

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 55, \pi = \frac{24}{55} = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - \frac{0.07}{2} = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 - 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4364 + 1.81\sqrt{\frac{0.4364*0.5636}{55}} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

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3 years ago
Write 400 in scientific notation.
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= 4 × 10 to the power of 2

Step-by-step explanation:

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