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2 years ago

Write 400 in scientific notation.

Mathematics

1 answer:

OlgaM077 [116]2 years ago

3 0

= 4 × 10 to the power of 2

Step-by-step explanation:

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What is the undefined variable in this equation (6x2 +3x) ÷ (3x) simplified 3x + 1

ozzi

X is the undefined variable hope it helps

4 0

3 years ago

Lenny worked 7 hours on Wednesday, 6 hours on Thursday, and 9 hours on Friday. His gross pay for all three days was $196.90.

tatyana61 [14]

Answer:

$8.95

Step-by-step explanation:

you add 7+6+9=22 196.90 divided by 22 is 8.95 hope this helps

5 0

2 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago

Please answer these two questions..

madam [21]

1. 2t-2i
2. 6ab2(square)

8 0

3 years ago

A set of data has 12 pieces of data. Which of the following statements is NOT TRUE?

BARSIC [14]

To help you understand this, it is helpful to create a sample set of data:

__,__,__,(Q1 is here)__,__,__,(median is here)__, __,__,(Q3is here)__,__,__

A. The first 3 lines are 3 pieces of data in the first quartile.

B. here are 6 pieces of data between the 1st and 3rd quartiles.

D. There are 3 pieces of data in the upper quartile.

5 0

3 years ago