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3 years ago

what is 16/10 as a mixed number in simplest form. I don't get it?

2 answers:

6 0

16/10 as a mixed number is 1 6/10.

I got this answer by finding out how many times 10 goes into 16, evenly. I got 1, and put that as a whole number. 6 was leftover, so I put that for the numerator. Then, I kept the denominator same, which was 10.

1 6/10 simplified is 1 3/5.

I got this answer by finding out what number goes both into 10 and 6, evenly. The GCF, or Greatest Common Factor, was 2. I divided 6 by 2 and 10 by 2. I then got 3 and 5.
3 was the numerator, and 5 is the denominator.

Again, 16/10 in simplest form is 1 3/5.

VladimirAG [237]3 years ago

4 0

Answer:

1 and 6/10

Step-by-step explanation:

and it simplflys to 1 and 3/5

You might be interested in

For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?

Morgarella [4.7K]

Answer:

Step-by-step explanation:

We are asked that the value of (4n + 7) will be an integer > 1 and < 200, for how many integer values of n.

So, equating (4n + 7) with 200 we can get the value.

4n + 7 = 200

⇒ 4n = 193

⇒ n = 48.25

Hence, the value of n will be the largest integer less than 48.25.

Therefore, the number of integer values of n will be 48. (Answer)

3 0

4 years ago

If the original price of a watch is $130 and there is a 10% tax, what is the price of the watch, including tax?

kvasek [131]

Answer:

$143.00

Step-by-step explanation:

130+10%(13.00)=143.00

7 0

4 years ago

You have one type of nut that sells for $2.80/lb and another type of nut that sells for $9.60/lb. You would like to have 20.4 lb

max2010maxim [7]

Answer:11.396Ibs of nuts that cost $9.60/Ib and 9.014Ibs that cost $2.80/Ib

Step-by-step explanation:

First we find the cost of the supposed mixture we are to get by selling it $6.60/Ib which weighs 20.41Ibs

Which is 6.6 x 20.41 = $134.64

Now we label the amount of mixture we want to get with x and y

x = amount of nuts that cost $2.8/Ib

y = amount of nuts that cost $9.6/Ib

Now we know the amount of mixture needed is 20.41Ibs

So x + y = 20.41Ibs

And then since the price of the mixture to be gotten overall is $134.64

We develop an equation with x and y for that same amount

We know the first type of nut is $2.8/Ib

So for x amount we have 2.8x

For the second type of nut that is $9.6/Ib

For y amount we have 9.6y

So adding these to equate to $134.64

2.8x + 9.6y = 134.64

So we have two simultaneous equations

x + y = 20.41 (1)

2.8x + 9.6y = 57.148 (2)

We can solve either using elimination or factorization method

I'm using elimination method

Multiplying the first equation by 2.8 so that the coefficient of x for both equations will be the same

2.8x + 2.8y = 57.148

2.8x + 9.6y = 134.64

Subtracting both equations

-6.8y = -77.492

Dividing both sides by -6.8

y = -77.492/-6.8 =11.396

y = 11.396Ibs which is the amount of nuts that cost $9.6/Ib

Putting y = 11.396 in (1)

x + y = 20.41 (1)

x +11.396 = 20.41

Subtract 11.396 from both sides

x +11.396-11.396 = 20.41-11.396

x = 9.014Ibs which is the amount of nuts that cost $2.8/Ibs

8 0

4 years ago

I really need help quick

Natali [406]

Answer:

$\sf x=2+\sqrt{6},\:x=2-\sqrt{6}$

Explanation:

$\sf y = x^2 -4x$

given that y = 2

$\sf x^2 -4x = 2$

$\sf x^2 -4x -2 = 0$

using quadratic formula:

$\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \ \ \ when \ ax^2 + bx + c = 0$

$\rightarrow \sf x_{1,\:2}=\dfrac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-2\right)}}{2\cdot \:1}$

$\rightarrow \sf x_1=\dfrac{-\left(-4\right)+2\sqrt{6}}{2\cdot \:1},\:x_2=\dfrac{-\left(-4\right)-2\sqrt{6}}{2\cdot \:1}$

$\rightarrow \sf x=2+\sqrt{6},\:x=2-\sqrt{6}$

in decimals:

$\rightarrow \sf x=4.45 , \ -0.45$

5 0

2 years ago

Does anyone know the answer to both of these questions????

atroni [7]

Answer:

c d

Step-by-step explanation:

3 0

3 years ago