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Ratling [72]
3 years ago
6

Which of the below is not one of the properties of logarithms?

Mathematics
1 answer:
MrRa [10]3 years ago
8 0

Answer:

option-B

Step-by-step explanation:

we know that

Sum rule of logarithm:

log(a)+log(b)=log(a\times b)

which is same as

the log of a product (ab) is equal to the addition of log a nad log b

Subtraction rule of logarithm:

log(a)-log(b)=log(\frac{a}{b} )

which is same as

the log of the quotient of a and b is equal to the log of a minus the log of b

Exponent rule of logarithm:

log(a^b)=blog(a)

which is same as

the log of the quantity a raised to b is equal to the product of b and the log of a

so,

option-B is not correct

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Plz i need help and plz explain
Montano1993 [528]

\frac{ {x}^{2}  - 7x + 12}{ {x}^{2} - x - 12 }  \\  =  \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 }  \\  =  \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)}  \\  =  \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)}  \\  =  \frac{x - 3}{x + 3}

x² - x - 12 ≠ 0

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(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

(B)

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3 years ago
The ball used in a soccer game may not weigh more than 16 ounces or less
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In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

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From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
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Answer:

m<PRS+m<PRQ=m<QRS.

17 + 17 = 34

m<QRS=34

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