The missing justification in Julia's angle proof is; Corresponding Angles Theorem
<h3>What is the angle theorem used?</h3>
We know that m∠AGE ≅ m∠HGB because they have congruent angles and are vertical angles.
Similarly, m∠HGB ≅ m∠CHE are alternate interior angles because two congruent angles on the inner side of the parallel lines are formed by a transversal.
In the diagram, m∠AGE ≅ m∠CHE would have to be corresponding Angles Theorem because parallel lines cut by a transversal would create congruent corresponding angles. That means a pair of angles on the same side of one of two lines that is cut by a transversal and on the same side of the transversal.
Read more about Angle theorem at; brainly.com/question/24839702
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Step-by-step explanation:
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<span>a. n/4 ≤ -1
Multiply both sides by 4 => n ≤ - 4, which is all the real numbers less or equal than - 4.
That in the real number line is all the numbers to the left of - 4 (including -4)
The matching graph is the B.
b. -10n ≥ -100
Divide both sides by - 10 => n ≤ 10
That is all the real numbers less or equal than 10.
In the real number line it is all the numbers to the left of 10, including 10.
So, the matching graph is the A.
c. 5x ≥ 20
Divide both sides by 5 => x ≥ 4
That is all the real numbers greater or equal to 4.
In the real number line it is all the numbers to the right of 4, including 4.
The matching graph is C.</span>
Answer:
(-1,0) and (5,0)
Step-by-step explanation:
The roots are the points where the y-value is 0 and the point lies exactly on the x-axis.
(blank,0)
In this parabola, the points that are exactly on the x-axis is (-1,0) and (5,0)
Using f(x) = y, we know that a graph of the function contains the (x,y) points (2,5) and (6,-1). first find the slope of that line,
m = (y2 - y1)/(x2 - x1) ⇒ -6/4⇒-3/2
then using either point (I'll use the first one) solve for b in y = mx + b.
5 = (-3/2)(2) + b⇒ 5 = -3 + b⇒ 8 = b.
So y = (-3/2)x + 8 ⇒ f(x) = (-3/2)x + 8.
