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Sergio [31]
3 years ago
11

Jane and Ken share some money in the ratio of 5:3

Mathematics
2 answers:
Vlad [161]3 years ago
8 0
Jane and Ken share some money in the ration 5:3 Ken's share is $16 less than Jane's share. FInd each person's share.
The money is shared in the ratio 5:3
That means that Jane gets 5 parts of the total money and Ken gets three parts.
So then there are 8 parts of the money (5 + 3 = 8)
Jane has 2 parts more than Ken (5 - 3 = 2)
And those 2 parts are equal to $16 (the question says so)
So one part is equal to $8
Each person's share then is: Jane has 5 parts = $40, Ken has 3 parts = $24
dangina [55]3 years ago
4 0

Let Jane's share = x

Equation

5:3 :: x:(x - 16)

5/3 = x / (x - 16)    

Solve

Cross multiply

5*(x - 16) = 3*x

5x - 80 = 3x      Add 80 to both sides.

5x = 3x + 80      Subtract 3x from both sides.

5x - 3x = 80

2x = 80             Divide by 2

x = 80/2

x = 40

So Jane's share is 40 dollars and Ken's is 40 - 16 = 24 dollars<<< Answer


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3 0
3 years ago
How do you solve this problem? 7/10 x 1 1/3
12345 [234]

Answer:

77/30

Step-by-step explanation:

7/10 x 11/3 = 7x11 = 77 and 10x3 = 30

the answer is 77/30

5 0
3 years ago
Read 2 more answers
The sum of the ages of Berma, her mother Rinna and her father Erwin is 80. Two years from now, Rinna’s age will be 13 less than
jekas [21]

Answer: Berma is 5 years old

Rinna is 38 years old

Erwin is 37 years old

Step-by-step explanation:

Let x represent Berma's age

Let y represent Rinna's age

Let z represent Erwin's age

Since the sum of their ages is 80,

x + y + z = 80 - - - - - - -1

Two years from now, Rinna’s age will be 13 less than the sum of Erwin’s age and twice Berma’s age. This means that

y +2 = [ (z+2) + 2(x+2) ] - 13

y +2 = z + 2 + 2x + 4 - 13

2x - y + z = 13 + 2 - 4 -2

2x - y + z = 9 - - - - - - -2

Three years ago, 15 times Berma’s age was 5 less than the age of Rinna. It means that

15(x - 3) = (y - 3) - 5

15x - 45 = y - 3 - 5

15x - y = - 8 + 45

15x - y = 37 - - - - - - - -3

From equation 3, y = 15x - 37

Substituting y = 15x - 37 into equation 1 and equation 2, it becomes

x + 15x - 37 + z = 80

16x + z = 80 + 37 = 117 - - - - - - 4

2x - 15x + 37 + z = 9

-13x + 2 = -28 - - - - - - - - -5

subtracting equation 5 from equation 4,

29x = 145

x = 145/29 = 5

y = 15x - 37

y = 15×5 -37

y = 38

Substituting x= 5 and y = 38 into equation 1, it becomes

5 + 38 + z = 80

z = 80 - 43

z = 37

6 0
3 years ago
Please help ASAP!!!
Svetach [21]

Answer:

B

Step-by-step explanation:

Just make sure that the x value is not being repeated twice. because one of the given points is (4,9) you cannot have the point (4,0). X value cannot repeat in a valid function.

3 0
3 years ago
Can anyone plz help me asap with Part B and C.?
creativ13 [48]

Answer:

Please post a clearer screenshot...

Step-by-step explanation:

5 0
2 years ago
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