Question

rectangle ABCD and WXYZ have the same length. The width of rectange ABCD is 9 ft, and its area is 162 ft2. The width of rectangle WXYZ is 6 ft. What is the area of rectangle WXYZ?

Answer 1

Answer:

$108 ft^{2}$

Step-by-step explanation:

Given,

The length of rectangle ABCD and WXYZ is equal.

Given,

Width of rectangle ABCD $= 9 feet$

Area of the rectangle ABCD= $162 ft^{2}$

Length of rectangle ABCD $= \frac{Area}{width} \\= \frac{162}{9} \\= 18 feet$

Since,  length of rectangle ABCD and WXYZ is equal

Area of rectangle WXYZ

$(Length of ABCD) * 6ft \\= 18 ft * 6 ft \\= 108 ft^{2}$

Answer 2

For ABCD
9*L = 162 ft2
L = 18
for WXYZ
18*6=108 ft2
18108 ft2