Answer: Bridge is 21 years old
Step-by-step explanation:
Ok so after reading the question I already know that B (Bridget), A (Angad) and P (Paul) is 49 in the sum of age. I also know that B=A+5 and P=A-4. After that I can assume B=P+5+4. So now after we gather everything, the age of all of them is the same if we delete 5, 4, 4 (From B=P+5+4 and P=A-4). 49-5-4-4=36. So now lets assume they are all 12 (36/3=12). B is 5 years older so lets add 5 to B. B=17, A=12 and P=8. 8+12+17= 37. We now know that but 37 is 12 under 49, so lets add the average 12/3=4 so we add 4 to all of them. B=21 A=16 P=12. 21+16+12=49. So Bridge is 21 years old, Angad is 16 years old and Paul is 12 years old
Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
1/25
Step-by-step explanation:
square has 4 sides, if you add them all up you get 4/5.
1/5+1/5+1/5+1/5=4/5
so each side is 1/5
Area=length * width
A=1/5*1/5=1/25
Answer:
D
Step-by-step explanation:
