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4 years ago

Solve and explain your answer

Mathematics

1 answer:

anzhelika [568]4 years ago

6 0

Answer:

526

Step-by-step explanation:

4^5 / 2 + (3.5 * 4)

4^5 / 2 + (14)

1024 / 2 + 14

512 + 14

526

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How to increase 1200 by 2%

Sholpan [36]

First, find 2% of 1200. We do this by multiplying 1200 by .02. This gives us 24. Then, we add 24 to 1200, giving us 1224. (We add 24 since 24 is 2% of 1200, and we're increasing by that 2%)

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3 years ago

What is the missing number that would make these two expressions equivalent? 6+7=(8*6)+8*7)

lana66690 [7]

Answer:

add 4

Step-by-step explanation:

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3 years ago

How do you work out the question i used 8 bags of sand for 12 m squared how much would i need for 15 m squared ?

Leviafan [203]

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3 years ago

In surjective and injective functions is it possible for elements of the domain not to be mapped to an element of the range? If

maks197457 [2]

Answer:

Step-by-step explanation:

The definition of a function f from A to B, regardless to injectivity or surjectivity, is that the domain of f is A, in its entirety.

This means that if f:A→B, then for every a∈A, there is a unique b∈B such that the pair (a,b)∈f.

So the converse holds just for it to be a function from A to B.

3 0

4 years ago

Computing growth rates (I): Suppose Xt=(1.04)^t and Yt=(1.02)^tCalculate the growth rate of Zt in each of the following cases:(a

Doss [256]

Answer:

$z(t) = (0.9808)^t$

$z(t) = (1.0196)^t$

$z(t) = (0.9808)^t$

$z(t) = (1.03)^t$

$z(t) = (1.0404)^t$

$z(t) = (1.0001)^t$

Step-by-step explanation:

We are given the following in the question:

$x(t)=(1.04)^t\\y(t)t=(1.02)^t$

We have to find the growth rate z(t) in each of the following cases:

(a) z = xy

$z(t) = x(t)y(t)\\z(t) = (1.04)^t.(1.02)^t\\z(t) = (1.04\times 1.02)^t\\z(t) = (1.0608)^t$

(b) z=x/y

$z(t) =\displaystyle\frac{x(t)}{y(t)}\\\\z(t) = \frac{(1.04)^t}{(1.02)^t} = \bigg(\frac{1.04}{1.02}\bigg)^t\\\\z(t) = (1.0196)^t$

(c) z=y/x

$z(t) =\displaystyle\frac{y(t)}{x(t)}\\\\z(t) = \frac{(1.02)^t}{(1.04)^t} = \bigg(\frac{1.02}{1.04}\bigg)^t\\\\z(t) = (0.9808)^t$

(d) z=x^(1/2) y^(1/2)

$z(t) = (x(t))^{\frac{1}{2}}(y(t))^{\frac{1}{2}}\\z(t) = ((1.04)^t)^\frac{1}{2} ((1.02)^t)^\frac{1}{2}\\z(t) = (1.0608)^{\frac{t}{2}}\\z(t) = (1.03)^t$

(e) z=(x/y)^2

$z(t) =\bigg(\displaystyle\frac{x(t)}{y(t)}\bigg)^2\\\\z(t) =\bigg( \frac{(1.04)^t}{(1.02)^t}\bigg)^2 = \bigg(\frac{1.04}{1.02}\bigg)^{2t}\\\\z(t) = (1.0404)^t$

(f) z=x^(-1/3)y^(2/3)

$z(t) = (x(t))^{\frac{-1}{3}}(y(t))^{\frac{2}{3}}\\z(t) = ((1.04)^t)^{\frac{-1}{3}}((1.02)^t)^{\frac{2}{3}}\\z(t) = ((1.04)^{\frac{-1}{3}})^t((1.02)^{\frac{2}{3}})^t\\z(t) = (1.04^{\frac{-1}{3}}\times 1.02^{\frac{2}{3}})^t\\z(t) = (1.0001)^t$

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3 years ago