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larisa86 [58]
3 years ago
11

Which best describes what is happening in section b ?

Mathematics
1 answer:
levacccp [35]3 years ago
3 0
D, he is moving at a constant spees
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HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE please :3
zloy xaker [14]
D is the correct answer
7 0
3 years ago
To solve the equation X - 62 = 123, you would ?
Ratling [72]
X-62=123
+62 +62
_________
x=185
you need to add a positive 62 from each side so -62+62=0 and 123+62=185
therefore, x=185
:Done! hope this helps!
6 0
3 years ago
3(5j+2)=2(3j-6) how do i do this
ohaa [14]

3(5j+2)=2(3j-6) do distributed to remove parenthesis  15j+6=6j-3 . Then move all j to left side and the second term to right side 15j-6j=-3-6. Now solve both sides  9j= -9. Now divide both sides by 9 to get j alone to j =  -1

5 0
3 years ago
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Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2
boyakko [2]

<u>Given</u>:

The quadratic equation is x^{2}=-5 x-3

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

x^{2}+5 x+3=0

The solution of the equation can be determined using quadratic formula.

Thus, we get;

x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}

x=\frac{-5 \pm \sqrt{25-12}}{2 }

x=\frac{-5 \pm \sqrt{13}}{2 }

Thus, the two roots of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

Hence, the solutions of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

6 0
3 years ago
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Each gallon of paint covers $200$ square feet. I have to paint one side of a wall that is $12$ meters tall and $80$ meters long.
dsp73

Answer:

make those cheeks go in circuler motion

Step-by-step explanation:

5 0
3 years ago
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