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AlekseyPX
3 years ago
10

Someone please help me

Mathematics
1 answer:
Mars2501 [29]3 years ago
4 0

Answer:

x=-1,-2

Step-by-step explanation:

Multiply the given equation with (x+1) on both sides. We'll get,

x+2/x=-3

or,x^2+2=-3x

or,x^2+3x+2=0

or,x^2+2x+x+2=0

or,x(x+2)+1(x+2)=0

or,(x+2)(x+1)=0

or,x=-2,-1

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postnew [5]

Answer:

x1, x2 = 7.73 , 4.27

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 12x + 33

a = 1     b = -12    c = 33

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1

x1 = (12 + √(144 - 132)) / 2

x1 = (12 + √12) / 2

x1 = (12 + 3.46) / 2

x1 = 15.46 / 2

x1 = 7.73

x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1

x2 = (12 - √(144 - 132)) / 2

x2 = (12 - √12) / 2

x2 = (12 - 3.46) / 2

x2 = 8.54 / 2

x2 = 4.27

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