Answer: k = {8, -8}
<u>Step-by-step explanation:</u>
In order for a quadratic equation to have exactly one solution, the discriminant must equal zero. → b² - 4ac = 0
4x² + kx + 4 = 0
↓ ↓ ↓
a=4 b=k c=4
b² - 4ac = 0
k² - 4(4)(4) = 0
k² = 64
k = √64
k = ± 8
Answer:
Therefore Perimeter of Rectangle ABCD is 4 units
Step-by-step explanation:
Given:
ABCD is a Rectangle.
A(-6,-4),
B(-4,-4),
C(-4,-2), and
D (-6,-2).
To Find :
Perimeter of Rectangle = ?
Solution:
Perimeter of Rectangle is given as

Length = AB
Width = BC
Now By Distance Formula we have'

Substituting the values we get


Similarly


Therefore now
Length = AB = 2 unit
Width = BC = 2 unit
Substituting the values in Perimeter we get

Therefore Perimeter of Rectangle ABCD is 4 units
The order is: 9.036, 9.535, and 9.982.