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Otrada [13]
4 years ago
8

In a game, you draw a card with three consecutive numbers on it. You can choose one of the numbers and find the sum of its prime

factors. Then you can move that many spaces on a game board. You draw a card with the numbers 25, 26, 27. Which number should you choose if you want to move as many spaces as possible? Explain.
Mathematics
2 answers:
Alexandra [31]4 years ago
6 0

Answer:

26

Step-by-step explanation:

The prime factors of 25 are 5*5.  Their sum is 5+5 = 10.

The prime factors of 26 are 2*13.  Their sum is 2+13 = 15.

The prime factors of 27 are 3*3*3.  Their sum is 3+3+3 = 9.

The greatest of these sums is 15; this means 26 is the best choice.

Angelina_Jolie [31]4 years ago
3 0
So sum the prime factors up

25=5*5, 5+5=10
26=2*13, 2+13=15
27=3*3*3, 3+3+3=9

15>10>9

26 is biggest

pick 26
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<u>Answer:</u>

<u><em>41</em></u>

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<u>Explanation:</u>

To solve this problem we must first understand what the pattern is in the arithmetic sequence. Once we understand the pattern, we can then apply it to the final known term to find the next term.

Take a look at the arithmetic sequence given:

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<em />

Let's start by figuring out how they got the second term in the sequence. To do that, subtract the second term by the first term. This will reveal the pattern.

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<em>17 - 9 = 8</em>

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So, this means they added eight to get the next term. Therefore, the pattern should be 'add eight' to get the next term. Just to be sure the pattern we found is correct, apply it to the given arithmetic sequence.

<em>9, 17, 25, 33,...</em>

<em>9 </em><em>+ 8 = </em><em>17</em>

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<em />

So, since 'adding eight' every time gives us the next term, the pattern is correct.

Finally, let's continue the pattern to find the next term.

<em>9, 17, 25, 33,...</em>

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<em>33 </em><em>+ 8 = </em><em>41</em>

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<em>9, 17, 25, 33, 41,...</em>

<em />

Therefore, the next term in the arithmetic sequence is <u><em>41</em></u>.

3 0
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