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2 years ago

A park charges $8 per hour to rent a bike

Mathematics

2 answers:

Verdich [7]2 years ago

5 0

The answer would be c=8h

Aloiza [94]2 years ago

4 0

Cost equals 8$ per(times) hour

c=8j

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If you have $.25 on your debit card do you have enough money to buy a Baseball glove Yes or no

Novosadov [1.4K]

Answer:

no, depends on what the ball costs but no because its .25 (meaning cents) not 25.00 (meaning dollars)

Step-by-step explanation:

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3 years ago

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Help me please!! As soon as you can!!

Mrrafil [7]

The answer: X plus X+4

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3 years ago

Mr. Richards purchased 8 T-shirts for the volleyball team. The total cost of the T-shirts was $70.56. How much did each shirt co

bezimeni [28]

Answer:

$8.82

Step-by-step explanation:

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3 years ago

Given 6(x) = (x+41, what is b(-10)?

prisoha [69]

The value of $b(-10)$ is 31

Explanation:

The given expression is $b(x)=x+41$

We need to determine the value of $b(-10)$

The value of $b(-10)$ can be determined by substituting $x=-10$ in the expression $b(x)=x+41$

Thus, we have,

$b(-10)=-10+41$

Adding the terms, we have,

$b(-10)=31$

Thus, the value is 31.

Therefore, the simplified value of the expression by substituting $x=-10$ in the expression $b(x)=x+41$ is 31.

7 0

3 years ago

Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.

Elden [556K]

Answer:

The answer is " $cirtical\ points \ (x,g(x))\equiv (e,0),(e+3,\frac{27}{e^3})$ "

Step-by-step explanation:

Given:

$g(x) = (x-e)^3e^{-(x-e)}$

Find critical points:

$g(x) = (x-e)^3e^{(e-x)}$

differentiate the value with respect of x:

$\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r} \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]$

critical points $g'(x)=0$

$\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3$

So,

The critical points of $(x,g(x))\equiv (e,0),(e+3,\frac{27}{e^3})$

7 0

3 years ago