<u>Answer-</u>
At
the curve has maximum curvature.
<u>Solution-</u>
The formula for curvature =

Here,

Then,

Putting the values,

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

Now, equating this to 0






Solving this eq,
we get 
∴ At
the curvature is maximum.
Answer: 
Step-by-step explanation:
By definition the domain of an inverse function
is the range of f(x) and the range of the inverse function is equal to the domain of the principal function f(x).
If you have a function
, then to find the inverse function, follow these steps:
1. Make 


2. Solve for the variable "x":

3. Exchange the variable "x" with the variable "y":

4. Exchange "y" with
. Then the inverse function is:

To do this, change into common denominators. The common denominator is 21 so change the problem from 1/3 + 1/7 to 7/21 + 3/21. This gives you 10/21. It is already in simplest form.
Answer:
the probablity of rolling a one is 1/6
Step-by-step explanation:
Answer:
The correct answer to your question is A because your asking for the vertex of the equation.
Step-by-step explanation:
Vertex Algebraic Equations